How do I solve for x in a quadratic equation

Mathematics

2 answers:

Ymorist [56]3 years ago

3 0

for the value of x is to factor the quadratic, set each factor equal to zero, and then solve each factor.

AysviL [449]3 years ago

3 0

U add each side and than divide by 2 and that’s will be ur x

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Elan Coil [88]

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3 years ago

Read 2 more answers

Find the inverse of the function x2 + y2 = 4 and the domain of the inverse for 0 ≤ x ≤ 2.

alexandr402 [8]

To get the inverse "relation" of an expression, we first off, do a quick switcharoo of the variables, and then solve for "y", so let's proceed,

$\bf x^2+y^2=4\qquad inverse\implies \boxed{y}^2+\boxed{x}^2=4
\\\\\\
y^2=4-x^2\implies y=\pm\sqrt{4-x^2}$

and yes, the domain for the range 0 ⩽ x ⩽ 2, let's get instead the "range" of the original function,

 $\bf x^2+y^2=4\implies 0^2+y^2=4\implies y=\pm\sqrt{4}\implies \boxed{y=\pm 2}
\\\\\\
x^2+y^2=4\implies 2^2+y^2=4\implies 4+y^2=4\implies \boxed{y=0}\\\\
-------------------------------\\\\
\stackrel{\textit{range of original}}{-2\le y \le 2}~~=~~\stackrel{\textit{domain of its inverse}}{-2\le x \le 2}$

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3 years ago

Find the limit as t approaches 8 for the function f(t)=7(t-1)(t-1)

Ratling [72]

Answer:

7³

Step-by-step explanation:

You could answer this after a quick inspection. 7 remains constant as t approaches 8. Each of the (t -1) terms will approach 7. So, multiplying these factors together, you'll get 7(7)(7) = 7³3 as your answer, the limit as t approaches 8 of the given expression.

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3 years ago

PLEASE HELP!!!!! will mark brainliest!!!!!

Nataly [62]

Answer:

x. f(×)

6. 9

7. 7

8. 5

9. 3

10. 1

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