Answer:
A is the midpoint
Step-by-step explanation:
Given
A(5.2) B(6,-3) and C(4.7)
Required
Which is the midpoint
Midpoint is calculated using:
![(x,y) = \frac{1}{2}(x_1+x_2,y_1+y_2)](https://tex.z-dn.net/?f=%28x%2Cy%29%20%3D%20%5Cfrac%7B1%7D%7B2%7D%28x_1%2Bx_2%2Cy_1%2By_2%29)
Testing A as the midpoint, we have:
![(5,2) = \frac{1}{2}(6+4,-3+7)](https://tex.z-dn.net/?f=%285%2C2%29%20%3D%20%5Cfrac%7B1%7D%7B2%7D%286%2B4%2C-3%2B7%29)
![(5,2) = \frac{1}{2}(10,4)](https://tex.z-dn.net/?f=%285%2C2%29%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2810%2C4%29)
![(5,2) = (\frac{1}{2}*10,\frac{1}{2}*4)](https://tex.z-dn.net/?f=%285%2C2%29%20%3D%20%28%5Cfrac%7B1%7D%7B2%7D%2A10%2C%5Cfrac%7B1%7D%7B2%7D%2A4%29)
![(5,2) = (5,2)](https://tex.z-dn.net/?f=%285%2C2%29%20%3D%20%285%2C2%29)
<em>The above equation is true. Hence, A is the midpoint of B and C</em>
Answer:
140
Step-by-step explanation:
Side of the square: s
Area of the square: As=s^2
Diameter of the circle: d=s
Area of the circle: Ac=pi d^2/4
Ac=pi s^2/4; pi=3.1416
Ac=3.1416 s^2/4
Ac=0.7854 s^2
<span>The likelihood that a point chosen inside the square will also be inside the circle: P=?
P=Ac/As=0.7854 s^2 / s^2
P=0.7854
P=0.7854 * 100%
P=78.54%
</span>The likelihood that a point chosen inside the square will also be inside the circle is 0.7854 or 78.54%
Answer:
B
Step-by-step explanation:
By studying the diagram, you will find they are perpendicular.