The student is incorrect, the actual x-intercept is (5, 0).
<h3>Is the student correct or incorrect?</h3>
Here we have the equation:
x + 2y = 5
The student says that the x-intercept is the point (0, 5).
So if you look at the point you already can see that the student is incorrect, this is because the x-intercept always must have a y-value of 0. (the graph only intercepts the x-axis when y = 0).
So the point (0, 5) can't be an x-intercept.
For the given function:
x +2y = 5
The x-intercept is given by:
x + 2*0 = 5
x = 5
So it is (5 , 0).
If you want to learn more about x-intercepts:
brainly.com/question/3951754
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The answer is 114 just divide 228 by 2
Answer:
he payed 34$ for the jacket
Step-by-step explanation:
I found 37.4 m.
I tried using trigonometry and the tangent of an angle (in this case 39°):
Answer:
b = -12
Step-by-step explanation:
The axis of symmetry goes through the point that represents the x value of the vertex when you complete the square.
y = (x - 6)^2 + 10 + c
y = x^2 - 12x + 36 + 10 - 36
y = (x^2 - 12x + 36) - 26
y = (x - 6)^2 - 26
