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castortr0y [4]
3 years ago
12

Type SSS, SAS, ASA, SAA, or HL to

Mathematics
1 answer:
Tems11 [23]3 years ago
6 0

9514 1404 393

Answer:

  ASA

Step-by-step explanation:

The shared angle, the marked angle, and the marked sides between those angles are congruent. That is, you have congruent Angle, Side, Angle, so the ASA postulate applies.

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HELP ME PLSSSS :))))))​
guapka [62]
If u add them all up and multiple by two in total he walks 43 blocks
6 0
3 years ago
at the science school, there is one microscope for every 5 students. The principal figures that in order to have one for every 4
Gennadij [26K]
Answer: 120 students

Explanation:

Let x be the number of scopes
Let a be the number of student at school

1x = 5 students
But 5x = a

1x = 4 students
But the principal needs 6 additional scope so that all the students can use it.

=> (x + 6) = 4 students
=> 4(x + 6) = a

Thus,
5x = 4(x + 6)
5x = 4x + 24
5x - 4x = 24
x = 24

So, there are 24 scopes.

Plug x in both equation and compare:

5x = a
5(24) = a
120 = a

4(x + 6) = a
4(24 + 6) = a
4(30) = a
120 = a

Therefore, the students at the school are 120
6 0
3 years ago
Identify the restrictions on the domain of f(x) = x+2/x-3<br> x≠-2<br> x≠2<br> x≠-3<br> x≠3
erma4kov [3.2K]

Answer:

  x ≠ 3

Step-by-step explanation:

The denominator of ...

  f(x) = (x+2)/(x -3)

is zero when x=3, so the function is not defined there. Values of x for which the function is not defined are not part of the domain.

The restriction is: x ≠ 3.

_____

Please note that parentheses are required around numerators and denominators when a rational function is written in plain text. When it is typeset:

  f(x)=\dfrac{x+2}{x-3}

the division bar serves as a grouping symbol. In plain text, we cannot tell where numerator and denominator begin and end unless some other grouping symbol (parentheses) is used.

4 0
3 years ago
Howdy!
posledela

Answer:

A) Central angle has same measure as intercepted arc.

  • mCE = mCD + mDE = 20° + 90° = 110°

B) Opposite angles of cyclic quadrilateral are supplementary.

  • mRL = 2*m∠PQR - mPL = 2*74° - 72° = 76°
  • m∠QPL = (1/2)mQRL = (1/2)(90° + 76°) = 83°
  • m∠QRL = 180° - m∠QPL = 180° - 83° = 97°
  • mQP = 360° - (90° + 76° + 72°) = 122°

C)

  • m∠MLN = m∠MRN as same arc MN is intercepted
  • m∠LMN is right angle as opposite side is diameter.
  • ∠MNL is complementary with ∠MLN which is same as ∠MRN
  • m∠MNL = 90° - 47° = 43°

D) Tangent secant angle is half of the intercepted arc.

<em>It seems wrong. Should be mQP instead of mQR</em>

  • mQP = 2*m∠RQP = 2*74° = 148°
8 0
3 years ago
Mark counts six ducks in a pond and some ducks on the grass. There are ducks all l4. Draw a picture to show the two groups of du
murzikaleks [220]
So 6 in pond
some on grass
# in pond+# in grass=14
6 in pond
subsitute 6 for pond
6+# in greass=14
subtract 6 from both sides
6-6+# in grass=14-6
0+# in grass=8
# in grass=8
there are 8 ducks in grass

so you would draw a circle for the pond and put 6 circles in there to represent the ducks, then , outside of that big circle, draw 8 circles to represent the 8 ducks on the grass (maybe label the big circle as pond and outside as grass)
6 0
4 years ago
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