Answer:
(21x^4y + 7x^3y^2 − 28x^2y^2) ÷ 7xy = 3x^3 + x^2y − 4xy
Step-by-step explanation:
(9xy^2 + 12x^3y^4 − 6x) ÷ 3x = 4x^2y^4 + 3y^2 − 2 (False: 9xy^2:3x=3y^2)
25x^4y^2 + 10x^2y^4 − 15y) ÷ 5y = 5x^4y + 2x^3y^2 − 3 (False: 10x^2y^4:5y=2x^2y^3)
(16x^4y^2 + 24x^2y^2 − 8xy^2) ÷ 4xy = 4x^4y + 6xy− 2y(False: 16x^4y^2:4xy=4x^3y)
(21x^4y + 7x^3y^2 − 28x^2y^2) ÷ 7xy = 3x^3 + x^2y − 4xy (True)
Lets see!
We need to use the pythagorean theorem (a^2+b^2=c^2) to check.
So..
15^2+ 17^2 = 19^2
225+ 289= 361
Hm 225 and 289 do NOT equal 361 therefore it is NOT a right triangle.
Answer:
$4,400
Step-by-step explanation:
Key: B stands for balance.
b+308=4708
b=4,708-308
b=$4,400
Your answer would be
A. Adding 7x to both sides of the equation
And in doing so, you'd start your first step to having "like terms" on "like sides"
by having all "x's" on the right side of your equivalent sign "="
