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kodGreya [7K]
3 years ago
6

Evaluate the function ƒ(x) = − (x2 − 1) and simplify at the indicated value: ƒ(−a) = ?

Mathematics
2 answers:
katen-ka-za [31]3 years ago
6 0
F(x)=-x^2+1
for -a
remember pemdas
exponenets before multiply

for -x^2, it is (x^2) first, then times -1

f(x)=-(-a)^2+1
f(x)=-(a^2)+1
f(x)=-a^2+1
salantis [7]3 years ago
4 0

Answer:

f(-a)=-a^2+1

Step-by-step explanation:

We have been a function f(x)=-(x^2-1). We are asked to simplify our function at the indicated value f(-a).

To find f(-a) for our given function, we will substitute x=-a in our given function as:

f(-a)=-((-a)^2-1)

We know that a negative number raised to an even power results in positive, so our function would be:

f(-a)=-(a^2-1)

Using distributive property a(b+c)=ab+ac, we will get:

f(-a)=-1*a^2-1*-1

f(-a)=-a^2+1

Therefore, the value of f(-a) is -a^2+1.

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