Question

Evaluate the function ƒ(x) = − (x2 − 1) and simplify at the indicated value: ƒ(−a) = ?

Answer 1

F(x)=-x^2+1
for -a
remember pemdas
exponenets before multiply

for -x^2, it is (x^2) first, then times -1

f(x)=-(-a)^2+1
f(x)=-(a^2)+1
f(x)=-a^2+1

Answer 2

Answer:

$f(-a)=-a^2+1$

Step-by-step explanation:

We have been a function $f(x)=-(x^2-1)$. We are asked to simplify our function at the indicated value $f(-a)$.

To find $f(-a)$ for our given function, we will substitute $x=-a$ in our given function as:

$f(-a)=-((-a)^2-1)$

We know that a negative number raised to an even power results in positive, so our function would be:

$f(-a)=-(a^2-1)$

Using distributive property $a(b+c)=ab+ac$, we will get:

$f(-a)=-1*a^2-1*-1$

$f(-a)=-a^2+1$

Therefore, the value of $f(-a)$ is $-a^2+1$.