UHHHHH IM GONNA FAIL MATH YALL Just answer it ig-? I WILL MARK AS BRAINLIEST
1 answer:
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Answer:
82% of scores were between 286 and 322
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 310 and a standard deviation of 12.
This means that
What percent of scores were between 286 and 322?
The proportion is the pvalue of Z when X = 322 subtracted by the pvalue of Z when X = 286. So
X = 322
has a pvalue of 0.8413
X = 286
has a pvalue of 0.0228
0.8413 - 0.0228 = 0.8185
0.8185*100% = 81.85%
Rounding to the nearest whole number
82% of scores were between 286 and 322