Answer:
<h2>7.4inches</h2>
Step-by-step explanation:
Check the attachment for the diagram. Sine rule will be used to get the unknown side of the triangle.
According to the rule;

Given w = 3 in, ∠W=23° and ∠U=73°, on substituting into the equation above to get u we have;

The length of u is 7.4inches to nearest 10th of an inch
Ball=sphere
Vsphere=pir^3
d/2=r
d=9
9/2=4.5=r
V=pi4.5^3
V=pi91.125
aprox pi=3.141592
V=286.227
round
V=286 in^3
It’s 52 because there are two sides with 64 degrees (the bottom two sides) and you add those to sides together and subtract your combine angle of the bottom 2 sides by 180 degrees which is the degree of all triangles combine and get 52
Answer:
100 x 100 x 100 number cubes
Step-by-step explanation:
It's basically a volume problem. The question is asking if you made a big cube filled with smaller cubes , specifically 1,000,000 of them, what are the dimensions of this big cube. Or in other words the volume is 1,000,000. Now how do we find the volume of a cube? length times width times height, and witht he cubes each of those are the same so we can call them all x.
Now we just set up the equation where we have the equation whatever one side is times itself three times, (or x cubed) it will equal 1,000,000 or x^3=1,000,000,000. Now you just take the cube root of 1,000,000 which gets us 100. so the length, width and height are 100 small cubes.
Answer:
$36.75
Step-by-step explanation:
If you take the original cost 35.00 and add 5% to it, you would get 36.75. If you think about it, it has to be above $35 since the sales tax would be more.