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garik1379 [7]
3 years ago
6

Need this ASAP please...​

Mathematics
2 answers:
ollegr [7]3 years ago
6 0
X = 12

There you go I hope you get 100% ;)
Komok [63]3 years ago
4 0

Answer:

I think <em>x</em> might be 2 i don't know...

Step-by-step explanation:

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Somebody please help me
Elenna [48]

Answer:

I believe it's 4,080

Step-by-step explanation:

you just add the two numbers

7 0
3 years ago
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A walkway forms one diagonal of a square playground. the walkway is 16 m long. how long is a side of the​ playground?
prohojiy [21]

Side of the playground would be : a²+a² = 16²

2a² = 256

a² = 128

a = √128

a = 11.31 m

3 0
3 years ago
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Please help i’ll mark u brainliest
Fantom [35]
0 19 50 24 that’s as far as I could get
5 0
2 years ago
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Together, a house and the lot it is on costs $40,000. If the house costs seven times as much as the lot, how much does the lot c
padilas [110]

The lot costs 5000 dollars.

<u>Step-by-step explanation:</u>

The cost of a House and the lot = $40,000.

Let us assume the cost of lot as 'x'

Given that, The cost of the house is 7 times as much as the lot.

Therefore, The cost of the house= 7x

The cost of both the house and the lot= x + 7x

$40,000 = x + 7x

40,000 = 8x

x = 40,000/8

x = 5,000

The lot costs $5000.

4 0
3 years ago
In a group of 10 ​kittens, 5 are female. Two kittens are chosen at random. ​a) Create a probability model for the number of male
olya-2409 [2.1K]

Answer:

(b) Expected number of male kitten E(x) = 1

(c) Standard deviation is ±\frac{2}{3}.

Step-by-step explanation:

Given that,

Number of kittens in a group are 10. Out of these 5 are female.

To find:- (a) create a probability model of male kitten chosen.

    So,  total number of kitten = 10

           number of female kitten = 5    

then, Number of male kitten = 10-5= 5

Now total number of ways to choosing two kittens from group of 10 = ^{10} C_{2}

                                                                                                                 = \frac{10!}{2!\times8!}

                                                                                                                 = 45

for choosing (i) No male P(x=0) = P(Two female) =  \frac{^{5} C_{2}}{45}

                                                                           = \frac{2}{9}

                     (ii) 1 male P(x=1) = P(1 male and 1 female) = \frac{^{5} C_{1}\times^{5} C_{1}}{45} =  \frac{25}{45} =\frac{5}{9}

                     (iii) 2 male P(x=2)= P(2 male) =\frac{^{5} C_{2}}{45} =  \frac{2}{9}

      x_{i}                             0                     1                      2

P(X=x_{i})                           \frac{2}{9}                      \frac{5}{9}                      \frac{2}{9}

(b) what is expected number of male kittens chosen ?

    Expected number of male kitten E(x) =  o\times \frac{2}{9} + 1\times \frac{5}{9} + 2\times\frac{2}{9}

                                                                  = 1

(c) what is standard deviation ?

                              \sigma(x) = \sqrt{ (E(x^{2} )-(Ex)^{2})

No,                          

                               Ex^{2} =o\times \frac{2}{9} + 1\times \frac{5}{9} + 4\times\frac{2}{9}

                                       = \frac{13}{9}

                               \sigma(x)=\sqrt{\frac{13}{9} - 1 }=\sqrt{\frac{4}{9} }  

                                       = ± \frac{2}{3}

                               

6 0
3 years ago
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