Answer:
630 minutes.
Step-by-step explanation:
That would be the lowest common multiple of 10, 14 and 18
10 = 2 x 5
14= 2 x 7
18 = 2 x 3 x 3
The LCM = 2 x 3 x 3 x 5 x 7
= 630.
I did this excat problem in school but my teacher just gave us the answer which is X<2
Answer:
Step-by-step explanation:
We can get this done by using the code
def digits(n):
count = 0
if n == 0:
return 1
while (n > 0):
count += 1
n= n//10
return count
Also, another way of putting it is by saying
def digits(n):
return len(str(n))
------------------------------------------
print(digits(25)) # Should print 2
print(digits(144)) # Should print 3
print(digits(1000)) # Should print 4
print(digits(0)) # Should print 1
Doing this way, we've told the system to count the number of figures that exist in the number. If it's 1000 to 9999, then it records it as 4 digits. If it's 100 - 999, then it records it as 3 digits. If it's 10 - 99, it records as 2 digits. If it's 0 - 9, then it has to record it as a single digit.
Thanks
Answer:
rhombus
Step-by-step explanation:
A quadrilateral with equal-length sides is a <em>rhombus</em>.
_____
A square is a special case of a rhombus.
Answer:
1079
Step-by-step explanation:
Hello,
18-5 = 13
31-18=13
44-31=13
161=5+13*12
So we need to compute
Thanks
