Given that the function g(x)=x-3/x+4, the evaluation gives:
- g(9) = 6/13.
- g(3) = 0.
- g(-4) = undefined.
- g(-18.75) = 1.07.
- g(x+h) = x+h-3/x+h+4
<h3>How to evaluate the function?</h3>
In this exercise, you're required to determine the value of the function g at different intervals. Thus, we would substitute the given value into the function and then evaluate as follows:
When g = 9, we have:
g(x)=x-3/x+4
g(9) = 9-3/9+4
g(9) = 6/13.
When g = 3, we have:
g(x)=x-3/x+4
g(3) = 3-3/3+4
g(3) = 0/13.
g(3) = 0.
When g = -4, we have:
g(x)=x-3/x+4
g(-4) = -4-3/-4+4
g(-4) = -1/0.
g(-4) = undefined.
When g = -18.75, we have:
g(x)=x-3/x+4
g(-18.75) = -18.75-3/-18.75+4
g(-18.75) = -15.75/-14.75.
g(-18.75) = 1.07.
When g = x+h, we have:
g(x)=x-3/x+4
g(x+h) = x+h-3/x+h+4
Read more on function here: brainly.com/question/17610972
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Given data
1. The mean
2. The median
3. The sample standard deviation
![\begin{gathered} SD\text{ =}\sqrt[]{\frac{\sum f|x-\bar{x}|}{\sum f}} \\ \bar{x}=7.6515 \\ SD=\sqrt[]{4.8028} \\ SD=2.1915 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20SD%5Ctext%7B%20%3D%7D%5Csqrt%5B%5D%7B%5Cfrac%7B%5Csum%20f%7Cx-%5Cbar%7Bx%7D%7C%7D%7B%5Csum%20f%7D%7D%20%5C%5C%20%5Cbar%7Bx%7D%3D7.6515%20%5C%5C%20SD%3D%5Csqrt%5B%5D%7B4.8028%7D%20%5C%5C%20SD%3D2.1915%20%5Cend%7Bgathered%7D)
