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3 years ago

9

An object moves in simple harmonic motion with period 8 seconds and amplitude 6cm. At time = t 0 seconds, its displacement d fro

m rest is 0cm, and initially it moves in a negative direction.

1 answer:

Murrr4er [49]3 years ago

6 0

Answer:

123456789012345678901234567890

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3 years ago

True or false 33 over 3 equals 11.3?

Leno4ka [110]

Answer:

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3 years ago

Read 2 more answers

Hurry please!!! Fast response

AlladinOne [14]

Answer:

A.

$SA= \frac{2}{3} \pi rl+16 \pi r^2$

Step-by-step explanation:

Surface area of the original cone

$SA= \pi r l + \pi r^2... (1)$

When, radius is quadrupled and slant height is reduced to one sixth

$i. e. \: \:r = 4r\: \: \&\:\: l= \frac{1}{6}l$

Plug the above values of r and $l$ in equation (1), new surface area becomes:

$SA= \pi (4r)\times \frac{1}{6} l+ \pi (4r)^2$

$SA= \frac{4}{6} \pi rl+16 \pi r^2$

$\huge \purple {\boxed {SA= \frac{2}{3} \pi rl+16 \pi r^2}}$

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