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4 years ago

Round 26.55 to the nearest whole number

Mathematics

2 answers:

oksano4ka [1.4K]4 years ago

4 0

27. You round up when the number to its right is larger or is 5

Natasha_Volkova [10]4 years ago

3 0

The next larger whole number is 27 .
The next smaller whole number is 26 .

26.55 is closer to 27 than it is to 26 .

So the nearest whole number is 27 .

You might be interested in

Write 17 over 25 as a decimal

riadik2000 [5.3K]

Answer:

Its 0.68

Step-by-step explanation:

All you have to do is divide 17 by 25

8 0

4 years ago

Read 2 more answers

how do you get the answer for 1 5 over 8 and decimal 1.625 PLZ HELP I WILL GIVE YOU 50 POINTS FOR THIS

frutty [35]

1.625 as a fraction is 1 5/8

15/8 simplified is 1 7/8

if you are using the word "and" to represent multiplication here you go:

first i would change both fractions to a mixed number

13/8×15/8=195/64
simplify

your answer would be 3 3/64

if you are using "and" to represent adding here you go:

1.625 as a fraction is 1 5/8

first i would change 1 5/8 to a mixed number: 13/8

so then add 15/8+13/8=28/8

simplify:
28÷4=7
8÷4=2

7/2=3 1/2

i hope this helped

7 0

3 years ago

My favorite Pokemon card has a mass of about one and a half

s344n2d4d5 [400]

Answer:

grams cause its is really small

7 0

3 years ago

You are in charge of drinks for a community barbecue. You need to supply at least 120 cups of beverage to provide enough for the

Allushta [10]

5 gallons of lemonade equals to 80 cups. 64 Fl Oz of fruit juice equals to 8 cups. 80 plus 8 is only 88. You need 32 more.

3 0

3 years ago

7.2 Given a test that is normally distributed with a mean of 100 and a standard deviation of 10, find: (a) the probability that

kompoz [17]

Answer:

The probability that a single score drawn at random will be greater than 110

P( X > 110) = 0.1587

b)

The probability that a sample of 25 scores will have a mean greater than 105

P( x> 105) = 0.0062

c)

The probability that a sample of 64 scores will have a mean greater than 105

P( x⁻> 105) = 0.002

d)

The probability that the mean of a sample of 16 scores will be either less than 95 or greater than 105

P( 95 ≤ X≤ 105) = 0.9544

Step-by-step explanation:

a)

Given mean of the Normal distribution 'μ' = 100

Given standard deviation of the Normal distribution 'σ' = 10

Let 'X' be the random variable of the Normal distribution

let 'X' = 110

$Z = \frac{x-mean}{S.D} = \frac{110-100}{10} =1$

The probability that a single score drawn at random will be greater than 110

P( X > 110) = P( Z >1)

= 1 - P( Z < 1)

= 1 - ( 0.5 +A(1))

= 0.5 - A(1)

= 0.5 -0.3413

= 0.1587

let 'X' = 105

$Z = \frac{x-mean}{\frac{S.D}{\sqrt{n} } } = \frac{105-100}{\frac{10}{\sqrt{25} } } = 2.5$

The probability that a single score drawn at random will be greater than 110

P( x> 105) = P( z > 2.5)

= 1 - P( Z< 2.5)

= 1 - ( 0.5 + A( 2.5))

= 0.5 - A ( 2.5)

= 0.5 - 0.4938

= 0.0062

The probability that a single score drawn at random will be greater than 105

P( x> 105) = 0.0062

c)

let 'X' = 105

$Z = \frac{x-mean}{\frac{S.D}{\sqrt{n} } } = \frac{105-100}{\frac{10}{\sqrt{64} } } = 4$

The probability that a single score drawn at random will have a mean greater than 105

P( x> 105) = P( z > 4)

= 1 - P( Z< 4)

= 1 - ( 0.5 + A( 4))

= 0.5 - A ( 4)

= 0.5 - 0.498

= 0.002

The probability that a sample of 64 scores will have a mean greater than 105

P( x⁻> 105) = 0.002

d)

Let x₁ = 95

$Z = \frac{x_{1} -mean}{\frac{S.D}{\sqrt{n} } } = \frac{95-100}{\frac{10}{\sqrt{16} } } = -2$

Let x₂ = 105

$Z = \frac{x_{1} -mean}{\frac{S.D}{\sqrt{n} } } = \frac{105-100}{\frac{10}{\sqrt{16} } } = 2$

The probability that the mean of a sample of 16 scores will be either less than 95 or greater than 105

P( 95 ≤ X≤ 105) = P( -2≤z≤2)

= P(z≤2) - P(z≤-2)

= 0.5 + A( 2) - ( 0.5 - A( -2))

= A( 2) + A(-2) (∵A(-2) =A(2)

= A( 2) + A(2)

= 2 × A(2)

= 2×0.4772

= 0.9544

The probability that the mean of a sample of 16 scores will be either less than 95 or greater than 105

P( 95 ≤ X≤ 105) = 0.9544

7 0

3 years ago