All categories

3 years ago

Determine whether the two lines are parallel, perpendicular, coinciding, or only intersecting

Mathematics

1 answer:

Aleksandr-060686 [28]3 years ago

8 0

It's the third choice: only intersecting

You might be interested in

The expressions 4 (y - 3) and 4y - 12 are equivalent?True or False

Vinvika [58]

4(y - 3) and 4y - 12

yes they are equivalent

4(y - 3) = 4y - 12 using the distributive property the result is the same.

8 0

2 years ago

It takes the high-speed train x hours to travel the z miles from Town A to Town B at a constant rate, while it takes the regular

STatiana [176]

Answer:

Step-by-step explanation:

To solve this, we use ratio.

Firstly, we need to know the number of hours traveled. The total number of hours traveled = x+y

Ratio of this used by high speed train = x/(x +y).

Total distance traveled before they meet = [x/(x + y)] × z

For low speed train = [y/(x + y)] × z.

The difference would be distance by high speed train - distance by low speed train.

= z [ (x - y)/x + y)]

7 0

4 years ago

Please help me answer #2 and #3 with the process <br><br> Thank you it’s very much appreciated ! :)

makkiz [27]

Answer:

2). The oak tree is 33ft tall.

Step-by-step explanation:

Same process as I explained before

Answer:

3). The building is 30ft tall.

Step-by-step explanation:

Same process as I explained before

6 0

3 years ago

Multiply the following rational expressions and simplify the result

GarryVolchara [31]

Answer:

Step-by-step explanation:

We have to solve the given expression,

$\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}$

$\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}$ = $\frac{-y(-9+33y+3y^3)}{100-49y^2}.\frac{7y^2+17y+10}{14y(y+2)}$

= $\frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{7y^2+10y+7y+10}{14y(y+2)}$

= $\frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{y(7y+10)+1(7y+10)}{14y(y+2)}$

= $\frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{(y+1)(7y+10)}{14y(y+2)}$

= $\frac{-3y(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14y(y+2)}$

= $\frac{-3(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14(y+2)}$

= $\frac{3(3-11y-y^3)(y+1)}{(10-7y)(14(y+2)}$

3 0

3 years ago

Solve the given differential equation by separation of variables. csc(y) dx sec2(x) dy

Elden [556K]

Try this solution:
dx/siny=dy/cos2x;
sinydy=cos2xdx;
cosy=-1/2 sin2x+C.

3 0

3 years ago