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Amanda [17]
3 years ago
15

PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE HELP ME!!!!!!!! THATS ALL. I WILL GIVE POINTS, FAN, MEDAL. PLEASE, I AM SO BAD AT MATH

PLEASE HELP HELP HELP!!!!!!!!!!!!!!!!!!!
The weights of four packets of sugar are shown below:
Packet A: 4.35 pounds
Packet B: 4.42 pounds
Packet C: 4.48 pounds
Packet D: 4.39 pounds
Sandy has a scale that measures to the nearest tenth of a pound. If Sandy weighs each packet on her scale, the heaviest reading will be ____________ pounds.
Mathematics
2 answers:
aleksandrvk [35]3 years ago
7 0
"measures to the nearest tenth of a pound" tell us to round each of the weights listed to the nearest tenth (since the unit is already pounds, no conversion is needed). What this means is if the second number to the right of the decimal is 5 or greater, then we add 1 to the first number to the right of the decimal (and replace the second number with a zero). With all this said, it's much easier to show you, rather than to try to explain it. :D

4.35 is rounded up to 4.4 because the second number to the right of the decimal is 5.
Packet A = 4.4
Packet B = 4.4 
Packet C = 4.5
Packed D = 4.4
The question is asking what the heaviest reading will be, so from the whole list above we pick the highest number which is 4.5 pounds. Notice how the answer is not Packet C, or 4.48 pounds, but 4.5 pounds. It is asking for the reading, not the packet, nor the weight. Hope this helps. 
sashaice [31]3 years ago
7 0
The answer is 4.5 hope that help
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The length of AB is 9 centimeters. A dilation with a scale factor of 2 is applied to AB. What is the length of the image AB afte
OLEGan [10]

Answer:

18cm

Step-by-step explanation:

Given:

- The length of AB is 9 centimeters

- A dilation with a scale factor of 2

The length of the image AB after the dilation is applied:

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2 years ago
Length of the median CP
ehidna [41]

Given:

ΔABC \sim ΔDEF

To find:

The length of median CP

Solution:

In ΔABC,

AP = 12, BP = 12 and PC = 3x - 12

In ΔDEF,

DQ = 16, QE = 16 and FQ = 2x + 8

If two triangles are similar, then their median is proportional to the corresponding sides.

$\Rightarrow \frac{AP}{DQ} =\frac{PC}{FQ}

$\Rightarrow \frac{12}{16} =\frac{3x-12}{2x+8}

Do cross multiplication.

$\Rightarrow 12(2x+8)=16(3x-12)

$\Rightarrow 24x+96=48x-192

Add 192 on both sides.

$\Rightarrow 24x+96+192=48x-192+192

$\Rightarrow 24x+288=48x

Subtract 24x from both sides.

$\Rightarrow 24x+288- 24x=48x- 24x

$\Rightarrow 288=24x

Divide by 24 on both sides.

⇒ 12 = x

Substitute x = 12 in CP.

CP = 3(12) - 12

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The length of median CP is 24.

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What is the question?
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