Answer:
The chord is bisected.
Step-by-step explanation:
see the attached figure to better understand the problem
In the circle of the figure
The diameter is the segment DE
The chord is the segment AB
PA=PB=r ----> radius of the circle
Triangles PAC and PBC are congruent right triangles by SSS
Because
PA=PB
PC is a common side
AC=BC ----> Applying Pythagoras Theorem
therefore
The chord AB is bisected
Answer:
diagonal = = 12.8 inches (to the nearest tenth of an inch)
Step-by-step explanation:
As shown in the diagram attached to this solution:
Let the Length of the rectangular board = a
Let the width = b
Let the diagonal = d
where:
a = 10 inches
b = 8 inches
d = ?
Triangle ABC in the diagram is a right-angled triangle, therefore, applying Pythagoras theorem:
(hypotenuse)² = (Adjacent)² + (Opposite)²
d² = 10² + 8²
d² = 100 + 64
d² = 164
∴ d = √(164)
d = 12.806 inches
d = 12.8 inches (to the nearest tenth of an inch)
<em>N:B Rounding off to the nearest tenth of an inch is the same as rounding off to 1 decimal place.</em>
