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3 years ago

Can someone help me with 10-15 plz

Mathematics

1 answer:

polet [3.4K]3 years ago

4 0

Answer:

it is in the picture

Step-by-step explanation:

you just find the coordinates

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The high temperature for one town last year was 79°F The low temperature for the same town was - 3°F What was the difference bet

Ainat [17]

Answer:

79°c - (-3°c) = 82°c

Step-by-step explanation:

this is because we need to calculate the total gap between those numbers through number line. I have attached the photo, have a look over there.

6 0

3 years ago

Please help, thanks!<br><br> Factor completely<br><br> Sx²- 13x² + 15x²

Andru [333]

Answer:

x^2(S+2)

Step-by-step explanation:

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3 years ago

Item 10

vfiekz [6]

Answer:

21 Students

Step-by-step explanation:

140 x .15 = 21

5 0

3 years ago

A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the

Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= $\pi r^2h$

According to the problem,

$\pi r^2 h=25$

$\Rightarrow h=\frac{25}{\pi r^2}$

The surface area of the base of the can is = $\pi r^2$

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× $\pi r^2$ )

The lateral surface area of the can is = $2\pi rh$

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× $2\pi rh$ )

$=\$2.5 \pi r h$

Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

Putting $h=\frac{25}{\pi r^2}$

$\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}$

$\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}$

Differentiating with respect to r

$C'=4\pi r- \frac{62.5}{ r^2}$

Again differentiating with respect to r

$C''=4\pi + \frac{125}{ r^3}$

To find the minimize cost, we set C'=0

$4\pi r- \frac{62.5}{ r^2}=0$

$\Rightarrow 4\pi r=\frac{62.5}{ r^2}$

$\Rightarrow r^3=\frac{62.5}{ 4\pi}$

⇒r=1.71

Now,

$\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0$

When r=1.71 cm, the metal cost will be minimum.

Therefore,

$h=\frac{25}{\pi\times 1.71^2}$

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0

3 years ago

I don’t really understand this

PtichkaEL [24]

Answer:

you put the -3 where the x's are

Step-by-step explanation:

f(x)= -2(-3)^2 - 3(-3) + 6

i think i hope thats right

3 0

3 years ago

Read 2 more answers