Can someone help me with 10-15 plz

Mathematics

1 answer:

polet [3.4K]3 years ago

4 0

Answer:

it is in the picture

Step-by-step explanation:

you just find the coordinates

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What is the answer 0,12km² a m² show work

seraphim [82]

Answer:

120 000 m^2

Step-by-step explanation:

I ASSUME you're being asked to convert from km^2 to m^2.

For this you need to identify the conversion rate, which is 1 000 000 m^2 / 1 km ^2. Multiply by the thing you're converting from and cancel the units.

(1 000 000 m^2 / 1 km ^2) x 0,12 km^2 = 120 000 m^2 (the km^2 cancels out, leaving you only with your target unit of m^2)

8 0

2 years ago

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A 150 cm pendulum swings through an arc which measured 100pi cm. In exact radians, through what angle does it swing?

choli [55]

Answer:

Pendulum will swing by an angle 0.666π

Step-by-step explanation:

We have given arc = $100\pi cm$

And length of the pendulum l = 150 cm

Length of the pendulum will be equal to radius of the pendulum so r = 150 cm

Arc is given by $arc=radius\times angle$

So $100\pi =150\times\times \Theta$

$\Theta =0.666\pi$

So pendulum will swing by an angle 0.666π

5 0

3 years ago

Hey how do you get from standard form to vertex form?

vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be $\mathbf{ax^{2}+bx+c=0}$ where x is the variable.

Completing the square method is as follows:

send the constant term to other side of equal $\mathbf{ax^{2}+bx=-c}$
divide the whole equation be coefficient of $\mathbf{x^{2}}$ , this will give $\mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}$
add $\mathbf{(\frac{b}{2a})^{2}}$ to both side of equality $\mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}$
Make one fraction on the right side and compress the expression on the left side $\mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}$
rearrange the terms will give the vertex form of standard quadratic equation $\mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}$