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2 years ago

14

Two linear functions are represented below.

1 answer:

Evgen [1.6K]2 years ago

4 0

Answer:

5 th St. St. 3 in the basement in it 3rd floor St. Paul and St. 434inches 3rd Avenue and the main entrance of yall is a beautiful home in

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Two fair dice are thrown. Let X be a random variable giving the score on the rst die and Y be a random variable giving the large

defon

Answer:

idk

idkidk

Step-by-step explanation:

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2 years ago

Ex) A nursery plants a new tree and attaches a guy wire to help support the tree

o-na [289]

Answer:

d = 5,35 ft

Step-by-step explanation: See annex

Figure in annex is clear,

sin ∠42⁰ = d / 8

And

sin ∠42⁰ = 0.669

d/8 = 0,669

d = 0,669*8

d = 5,35 ft

8 0

2 years ago

Read 2 more answers

A pet store sells goldfish and hermit crabs,

Elis [28]

Answer:

$Cost = \$28$

Step-by-step explanation:

Given

Represent Goldfish with g and hermit crabs with h.

The first statement, we have:

$7g + 3h = 26$

The second statement, we have:

$4g + 5h = 28$

Required

Determine the selling price of 6 goldfish and 4 hermit crabs

The equations are:

$7g + 3h = 26$ --- (1)

$4g + 5h = 28$ --- (2)

Make g the subject in (2)

$4g + 5h = 28$

$4g = 28 - 5h$

Divide both sides by 4

$g = \frac{1}{4}(28 - 5h)$

Substitute $\frac{1}{4}(28 - 5h)$ for g in (1)

$7g + 3h = 26$

$7(\frac{1}{4}(28 - 5h)) + 3h = 26$

$\frac{7}{4}(28 - 5h) + 3h = 26$

Multiply through by 4

$4 * \frac{7}{4}(28 - 5h) + 4*3h = 26*4$

$7(28 - 5h) + 4*3h = 26*4$

Open bracket

$196 - 35h + 12h = 104$

$196 -23h = 104$

Collect Like Terms

$-23h = 104-196$

$-23h = -92$

Make h the subject

$h = \frac{-92}{-23}$

$h = \frac{92}{23}$

$h = 4$

Substitute 4 for h in $g = \frac{1}{4}(28 - 5h)$

$g = \frac{1}{4}(28 - 5*4)$

$g = \frac{1}{4}(28 - 20)$

$g = \frac{1}{4}(8)$

$g = 2$

This implies that:

1 goldfish = $2

1 hermit crab = $4

The cost of 6 goldfish and 4 hermit crabs is:

$Cost = 6g + 4h$

$Cost = 6*\$2 + 4*\$4$

$Cost = \$12 + \$16$

$Cost = \$28$

5 0

3 years ago

The population of two different villages is modeled by the equations shown

vlada-n [284]

Answer:

Year = 1995 and population = 315

Year = 2015 and population = 715

Step-by-step explanation:

It is given that the population of two different villages is modeled by the given equations:

$y=x^2-30x+540$

$y=20x+15$

The population of both villages are same after x years after 1980 if

$x^2-30x+540=20x+15$

$x^2-30x+540-20x-15=0$

$x^2-50x+525=0$

Splitting the middle term, we get

$x^2-15x-35x+525=0$

$x(x-15)-35(x-15)=0$

$(x-15)(x-35)=0$

$x=15,35$

It means, after 15 or 35 years, the population will same.

For x=15, years is $1980+15=1995$ and population is

$y=20(15)+15=315$

For x=35, years is $1980+35=2015$ and population is

$y=20(35)+15=715$ .

Therefore, population are equation in Year = 1995 and population = 315 or Year = 2015 and population = 715.

7 0

3 years ago

there are 18 boys and 12 girl in math class. what is the ratio of girls to total students. A. 18:30 B. 12:30 C. 30:12 D. 30:18 2

zmey [24]

Answer:

1. B

2. B and C

3.C

4.B the answer is 238 but i guess the rounded

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers