The value of the voltage is 18 - j volts if the current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms option (c) is correct.
<h3>What is a complex number?</h3>
It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.
We have:
The current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms.
As we know,
V = IR
V = (3 + j2)(4 - j3)
j² = -1 (complex part)
After simplification:
V = 18 - j volts
Thus, the value of the voltage is 18 - j volts if the current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms option (c) is correct.
Learn more about the complex number here:
brainly.com/question/10251853
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Answer:
-4>x and 5≤=x
Step-by-step explanation:
Hope this helps!!!
Answer:
(Picture below)
Step-by-step explanation:
To solve this you will first need to make a coordinate plane that is 10 by 10.
After you have done that you will need to know what slope intercept form is. Slope intercept form is 
and the equation that was given was 
. In the formula , 
is the slope or rise over run and b is where the line crosses the y axis.
Now that you know the basics of slope intercept form we can start graphing. so b in this equation is -6, so we will put the first point on -6. after we have done that we can start putting the points of the line. So since the slope is just -1x we will have to go down one and go to the right one about 3 times and just to finish it up go up and left on 3 times to. And there you have it.
The graph would be a shaded line all inclusive after -3
<u>Answer-</u>
<em>At 15.91° the ball was thrown.</em>
<u>Solution-</u>
<em>In the question it is given that the ball was released and caught from the same height.</em>
We know that,
Where,
R = Range of the projectile = 7.75 m,
u = Initial speed = 12 m/s
θ = Angle at which it was released
g = Acceleration due to gravity = 9.8 m/s²
Putting all the values,
