Answer:
11,424,400 possible passwords
Explanation:
Since all characters are letters and only lowercase
we have 26∧4 = 456,976 possibilities
For a 5-character password which is still lower case sensitive.
we have 26∧5 = 11,881,376 possibilities
Many more possible passwords = (11881376-456976)
= 11,424,400 possible passwords
Answer:
It allows the designer to focus on main logic without being distracted by programming languages syntax.
* Since it is language independent, it can be translated to any computer language code.
* It allows designer to express logic in plain natural language.
* It is easier to write actual code using pseudocode.
* Unlike algorithms, pseudocodes are concise so pseudocodes are more readable and easier to modify.
Explanation:
The appropriate answer is C ! all other are very limited but labour can be increased or decreased according to our will and it doesn't exhaust !
Answer
can we get a picture of the problem ?
Explanation:
Answer:
1.) 25 ; 15 ; 15
2.) 50 ; 15 ; 50
Explanation:
In the first function written :
The variable val was initially decaled or assigned a value of 25 and that was what was printed first.
However, after the example function was written, the val variable was finally assiagned a value of 15 within the function. However, it was also declared that the global variable takes uonthe val value. Hence, the val variable initially assigned a value, of 25 changes to 15 globally.
For the second code :
From the top:
Val was assigned a value of 50 ;
Hence,
print(val) gives an output of 50
Within the function definition which prints the value of val that is assigned a value of 25 within the function.
Since tbe global variable isnt reset.
Printing Val again outputs 50;since ito is outside the function.
