The value (9/10)*81 is greater than (5/6)*81
<h3>How to determine the greater value?</h3>
The values are given as:
(5/6)*81 and (9/10)*81
Remove the common factor in both values
So, we have:
5/6 and 9/10
Convert to decimals
0.83 and 0.9
0.9 is greater than 0.83
Hence, (9/10)*81 is greater than (5/6)*81
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Answer:
Hi there!
The correct answer is: 20
Step-by-step explanation:
knowing this a right triangle you can solve this problem in two ways
Method One: Pythagorean Theorem
a^2 + b^2 = c^2 then plug in the values
(12)^2 + (16)^2 = c^2 this will come out to be 400 = c^2
square root both sides and you get c = 20
Method Two: Pythagorean Identities
if you ever learned the Pythagorean identity 3,4,5
this triangle is indeed a 3,4,5 triangle it's just that each side is multiplied by the factor 4
so in this case since you know the missing side should be 5 you just multiply 5 by 4 and you get 20
Answer:
- p=0.7103 (4-game series)
- p=0.6480 (2-game series)
Step-by-step explanation:
Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

#We find probabilities for the different values of i:

Hence, probability of the stronger team winning overall is:

#Define Y as the random variable for winning 2/3 games.:

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480
The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)
√j+√j+14=3√j+10
2√j+14=3√j+10
minus 2√j both sides
14=√j+10
minus 10 both sides
4=√j
squaer both sides
16=j
answer is D, 16