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3 years ago

Please help! Math problem is attached!!

Mathematics

1 answer:

Tamiku [17]3 years ago

7 0

Answer:

Ounces of strawberry juice: 20 ounces

Ounces of water: 80 ounces

Step-by-step explanation:

For this problem, we can use the equation:

x + y = 100 ounces

Where x = The number of ounces of strawberry juice

and y = The number of ounces of water

Since we know that Molly uses four times as many ounces of water for each ounce of strawberry juice, we can conclude that:

y = 4x

With this information, we can use substitution to solve for x.

x + y = 100 ounces

x + (4x) = 100

Combine like-terms.

5x = 100

x = 20

Now that we know the value of x, we can figure out how many ounces of strawberry juice and how many ounces of water Molly needs.

Since x = The number of ounces of strawberry juice, Molly needs to use 20 ounces of strawberry juice.

Since y = The number of ounces of water, Molly needs to use 80 ounces of strawberry juice. (y = 4x | x = 20 | y = 4(20) | y = 80)

~Hope this helps!~

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2. Write a quadratic function that has -intercepts (- 3, 0) and (4, 0) and passes through the point (5, 8)

Reptile [31]

Answer:

$f(x)=x^2-x-12$

Step-by-step explanation:

<u>Quadratic Function</u>

Standard Form of Quadratic Function

The standard representation of a quadratic function is:

$f(x)=ax^2+bx+c$

where a,b, and c are constants.

When the zeros of f (x1 and x2) are given, it can be written as:

f(x)=a(x-x1)(x-x2)

Where a is a constant called the leading coefficient.

We are given the two roots of f: x1=-3 and x2=4, thus:

f(x)=a(x+3)(x-4)

We also know that f(5)=8, thus:

f(5)=a(5+3)(5-4)=8

Operating:

a(8)(1)=8

Solving:

a=1

The function is:

f(x)=1(x+3)(x-4)

Operating:

$\boxed{f(x)=x^2-x-12}$

5 0

2 years ago

Please help me with this

denis23 [38]

Answer:

20) $\displaystyle [4, 1]$

19) $\displaystyle [-5, 1]$

18) $\displaystyle [3, 2]$

17) $\displaystyle [-2, 1]$

16) $\displaystyle [7, 6]$

15) $\displaystyle [-3, 2]$

14) $\displaystyle [-3, -2]$

13) $\displaystyle NO\:SOLUTION$

12) $\displaystyle [-4, -1]$

11) $\displaystyle [7, -2]$

Step-by-step explanation:

20) {−2x - y = −9

{5x - 2y = 18

⅖[5x - 2y = 18]

{−2x - y = −9

{2x - ⅘y = 7⅕ >> New Equation

__________

$\displaystyle \frac{-1\frac{4}{5}y}{-1\frac{4}{5}} = \frac{-1\frac{4}{5}}{-1\frac{4}{5}}$

$\displaystyle y = 1$ [Plug this back into both equations above to get the x-coordinate of 4]; $\displaystyle 4 = x$

_______________________________________________

19) {−5x - 8y = 17

{2x - 7y = −17

−⅞[−5x - 8y = 17]

{4⅜x + 7y = −14⅞ >> New Equation

{2x - 7y = −17

_____________

$\displaystyle \frac{6\frac{3}{8}x}{6\frac{3}{8}} = \frac{-31\frac{7}{8}}{6\frac{3}{8}}$

$\displaystyle x = -5$ [Plug this back into both equations above to get the y-coordinate of 1]; $\displaystyle 1 = y$

_______________________________________________

18) {−2x + 6y = 6

{−7x + 8y = −5

−¾[−7x + 8y = −5]

{−2x + 6y = 6

{5¼x - 6y = 3¾ >> New Equation

____________

$\displaystyle \frac{3\frac{1}{4}x}{3\frac{1}{4}} = \frac{9\frac{3}{4}}{3\frac{1}{4}}$

$\displaystyle x = 3$ [Plug this back into both equations above to get the y-coordinate of 2]; $\displaystyle 2 = y$

_______________________________________________

17) {−3x - 4y = 2

{3x + 3y = −3

__________

$\displaystyle \frac{-y}{-1} = \frac{-1}{-1}$

$\displaystyle y = 1$ [Plug this back into both equations above to get the x-coordinate of −2]; $\displaystyle -2 = x$

_______________________________________________

16) {2x + y = 20

{6x - 5y = 12

−⅓[6x - 5y = 12]

{2x + y = 20

{−2x + 1⅔y = −4 >> New Equation

____________

$\displaystyle \frac{2\frac{2}{3}y}{2\frac{2}{3}} = \frac{16}{2\frac{2}{3}}$

$\displaystyle y = 6$ [Plug this back into both equations above to get the x-coordinate of 7]; $\displaystyle 7 = x$

_______________________________________________

15) {6x + 6y = −6

{5x + y = −13

−⅚[6x + 6y = −6]

{−5x - 5y = 5 >> New Equation

{5x + y = −13

_________

$\displaystyle \frac{-4y}{-4} = \frac{-8}{-4}$

$\displaystyle y = 2$ [Plug this back into both equations above to get the x-coordinate of −3]; $\displaystyle -3 = x$

_______________________________________________

14) {−3x + 3y = 3

{−5x + y = 13

−⅓[−3x + 3y = 3]

{x - y = −1 >> New Equation

{−5x + y = 13

_________

$\displaystyle \frac{-4x}{-4} = \frac{12}{-4}$

$\displaystyle x = -3$ [Plug this back into both equations above to get the y-coordinate of −2]; $\displaystyle -2 = y$

_______________________________________________

13) {−3x + 3y = 4

{−x + y = 3

−⅓[−3x + 3y = 4]

{x - y = −1⅓ >> New Equation

{−x + y = 3

________

$\displaystyle 1\frac{2}{3} ≠ 0; NO\:SOLUTION$

_______________________________________________

12) {−3x - 8y = 20

{−5x + y = 19

⅛[−3x - 8y = 20]

{−⅜x - y = 2½ >> New Equation

{−5x + y = 19

__________

$\displaystyle \frac{-5\frac{3}{8}x}{-5\frac{3}{8}} = \frac{21\frac{1}{2}}{-5\frac{3}{8}}$

$\displaystyle x = -4$ [Plug this back into both equations above to get the y-coordinate of −1]; $\displaystyle -1 = y$

_______________________________________________

11) {x + 3y = 1

{−3x - 3y = −15

___________

$\displaystyle \frac{-2x}{-2} = \frac{-14}{-2}$

$\displaystyle x = 7$ [Plug this back into both equations above to get the y-coordinate of −2]; $\displaystyle -2 = y$

I am delighted to assist you anytime my friend!

7 0

2 years ago

Is 103 divisible by 5

Nadya [2.5K]

Answer:no

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Can someone please help me with this ❤️❤️

kherson [118]

Answer:

See below for answers

Step-by-step explanation:

y=5(2)ˣ

y=5(2)⁻²=5(1/2²)=5(1/4)=5/4

y=5(2)⁻¹=5(1/2¹)=5(1/2)=5/2

y=5(2)⁰=5(1)=5

y=5(2)¹=5(2)=10

y=5(2)²=5(4)=20

8 0

2 years ago

PLEASE HELP ITS URGENT!!!!!!

Delvig [45]

Answer:

LCD-3x(x+2)

Final answer- x2-4x+4/ 3x2+6x

Step-by-step explanation:

okay so LCD is 3*x*(x+2)

= 3x(x+2)

so multiyling the fist expresion by x+2 and the second by x we get

2x+4+ x2-6x/ 3x(x+2)

= so

x2-4x+4/3x(x+2)

x2-4x+4/ 3x2+6x

if my answer helps please mark as brainliest.

4 0

3 years ago