Question

A fish jumps out of water. The function y = −16t 2 + 11t models the height, in feet, of the fish above water after t seconds. A) How long is the fish out of water? B) What is the maximum height of the fish above the water?

Answer 1

Answer:

A) The fish was out of water for 0.6875 seconds.

B) Maximum height = 5.672

Step-by-step explanation:

Height is modeled by;

y = -16t² + 11t

A) To find total time of the fish out of water, we need to find the x - intercept. That is the points where y = 0

So, 0 = -16t² + 11t

So the roots of this equation are;

t = 0 or 0.6875

Thus,the fish was out of water for 0.6875 seconds.

B) y = -16t² + 11t

The x coordinate of the vertex is at - b/2a

For y = -16t² + 11t

a = -16, b = 11, c = 0

So, -b/2a = -11/(2*-16) = 11/32

The maximum height will be at the y-coordinate of the vertex.

Thus, we need to find f(11/32)

f(11/32) = -16(11/32)² + 11(11/32) = 1.890625 + 3.78125 = 5.671875 ≈ 5.672