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3 years ago

What is x2+10x=0 with completing the square

1 answer:

7 0

$x^2 + 10x = 0 \\ 
x(x+10) = 0 \\ 
x = 0, -10$
You can't complete the square here. You would have to separate an x out to get two values of 0 and 10.

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G(x)=3x^2+6x−9 I need the vertex for this please

aleksley [76]

Answer:

-1, -12

Step-by-step explanation:

you take b which is 6 and make it negative, then you take a and multiply it by 2, which is 6. you then take the 2 numbers and put the -b over 2a in this formula -b/2a giving you -1 as your x value

after you do that, you input the -1 into the equation as x and the value you get out of that (-12) is the y value of the vertex

5 0

3 years ago

10+4.5m=21.25 Solve for M

enyata [817]

Answer:

m = 2.5

Step-by-step explanation:

10 + 4.5m = 21.25
=> 4.5m = 21.25 - 10
=> 4.5m = 11.25
=> m = 11.25/4.5
=> m = 2.5

Conclusion:

Therefore, m = 2.5

Hoped this helped.

$GeniusUser$

8 0

3 years ago

Sarah is a computer engineer and manager and works for a software company. She receives a

daser333 [38]

Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = $a$

Given that:

$a_4=129\\a_{10}=207$

Formula for $n^{th}$ term of an Arithmetic Progression is given as:

$a_n=a+(n-1)d$

Where $d$ will represent the number of projects increased every year.

and $n$ is the year number.

$a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)$

Subtracting (2) from (1):

$78 = 6d\\\Rightarrow d =13$

By equation (1):

$129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90$

Number of projects in the first year = 90

b)

Number of projects in the twelfth year =

$a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233$

Each project pays $500

Earnings in the twelfth year = 233 $\times$ 500 = $116500

Sum of an AP is given as:

$S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938$

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 $\times$ 1938 = $969000

8 0

3 years ago

Does 6n-18=4(n+2) equal 1n?

Mariulka [41]

Answer:

No.

Step-by-step explanation:

If we were to fill in the slots, the equation would be...

6x3-18=4

6 times three is 18, and 18 - 18 equals 0. So the answer would not be 1.

4 0

3 years ago

What is 3 multiplied by 1 8/11 as a mixed number or fraction

maks197457 [2]

Answer:

5 2/11

Step-by-step explanation:

6 0

3 years ago

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