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Serhud [2]
3 years ago
15

What is the only real number which, when divided by itself, is 2020 times itself?

Mathematics
2 answers:
malfutka [58]3 years ago
5 0

Answer:

20

Step-by-step explanation:

I'm not sure at all I'm sorry

scoundrel [369]3 years ago
3 0

Answer:

1/2020

Step-by-step explanation:

We can set up an equation, where x is the number that, when divided by itself, is 2020 times itself:

x/x = 2020*x

The left-hand side reduces to 1:

1 = 2020*x

Now, you can divide both sides by 2020:

x = 1/2020

To check, we can divide 1/2020 by itself:

\frac{\frac{1}{2020}} {\frac{1}{2020}} = \frac{1}{2020}\cdot \frac{2020}{1} = \frac{2020}{2020} = 1

1 is indeed 2020 times 1/2020.

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Given: sin(18m-12)=cos(7m+2), find the value of m.
V125BC [204]

Answer:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

Step-by-step explanation:

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-cos(7 m + 2) sin(12 - 18 m) = 0

Multiply both sides by -1:

cos(7 m + 2) sin(12 - 18 m) = 0

Split into two equations:

cos(7 m + 2) = 0 or sin(12 - 18 m) = 0

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or sin(12 - 18 m) = 0

Subtract 2 from both sides:

7 m = -2 + π/2 + π n_1 for n_1 element Z

or sin(12 - 18 m) = 0

Divide both sides by 7:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or sin(12 - 18 m) = 0

Take the inverse sine of both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or 12 - 18 m = π n_2 for n_2 element Z

Subtract 12 from both sides:

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or -18 m = π n_2 - 12 for n_2 element Z

Divide both sides by -18:

Answer: m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

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3 years ago
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Answer:

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Step-by-step explanation:

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