Direct variation is y = kx, where k is the constant of variation.
But now it says y varies directly with x2 (or 2x), so now the x in the equation is 2x.
The equation is y = k(2x)
Now you find k.
y = 96 when x = 4.
(96) = k(2*4)
96 = k(8)
k = 12
The equation is now y = 12(2x)
To find the value of y when x=2, plug 2 into the equation you made.
y = 12(2*2)
y = 48
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Now it's with a "quadratic variation," which is the same thing except x is squared.
The equation is y = kx^2
But y varies directly with x2 (same thing as 2x), so now it's y = k(2x)^2.
Now you find k by substituting y and x values that were given.
y = 180 when x = 6
(180) = k(2*6)^2
180 = k(12)^2
180 = k(144)
k = 1.25
k, 1.25, is the constant of variation.
Answer:
Kai suggested the best way to produce a random sample that is not biased
Step-by-step explanation:
Answer:
9,556
Step-by-step explanation:
First question:
4(3x-5) + (2x -2)(4 + 3x-5)
Simplify -----> 12x - 20 + (2x-2)(3x-1)
Multiply the second part -----> 12x - 20 + 6x^2 -8x + 2
Combine like terms --------> 6x^2 + 4x - 18
Each side of the addition sign represents one of the rectangles above which is then added to get the area of the entire figure.
Second question:
The average is the summation of each data value divided by the number of data values. So it would be
(4 + 5 + 9)/ 3
Simplify ------> 18/3
Divide --------> 6
