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Anastaziya [24]
3 years ago
6

Given f(x)=3^(x-2) and g(x)=f(3x)+4, write the function rule for function g and describe the types of transformations that occur

between function f and function g. See attached for proper functions.
Mathematics
1 answer:
klio [65]3 years ago
3 0

Answer with Step-by-step explanation:

We are given that

f(x)=3^{x-2}

g(x)=f(3x)+4

We have to write the rule for function g and describe the transformation between f and g.

Compress the function by scale factor 3 and the translation rule is given by

(x,y)\rightarrow (3x,y)

Then, we get h(x)=f(3x)=3^{3x-2}

Now, shift the y coordinate 4 units above the origin.

Then, the translation rule is given by

(x,y)\rightarrow (x,y+4)

Then , we get

g(x)=3^{3x-2}+4

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At the city museum, child admission is $6.10 and adult admission is $9.90. On Friday, 142 tickets were sold for a total sales of
antoniya [11.8K]

Answer:

no of child tickets sold were 58

Step-by-step explanation:

Let the number of child ticket sold be x

cost of 1 child ticket = $6.10

Total cost of x child ticket = x*cost of 1 child ticket = = $6.10x

Let the number of adult ticket sold be y

cost of 1 adult ticket = $9.90

Total cost of y adult ticket = y*cost of 1 adult ticket = = $9.90y

Given total ticket sold = 142

Thus,

number of child ticket sold +  number of adult ticket sold = 142

x + y = 142   - equation 1

x = 142 -y  

Total sales of ticket = $1185.40

total sales of ticket  = Total cost of x child ticket + Total cost of x a dult ticket

6.10x + 9.90y = 1185.40

in this equation substituting x = 142 - y from equation 1

6.10(142 - y )  + 9.90y = 1185.40

=>866.2 - 6.10y + 9.90y = 1185.40

=> 3.80y = 1185.40 - 866.2

=> 3.80y = 319.2

=> y = 319.2/3.80 = 84

Thus, y = 84

x = 142 - y  = 142 - 84 = 58

Thus, no of child tickets sold were 58

6 0
3 years ago
An airport limousine can accommodate up to four passengers on any one trip. The company will accept a maximum of six reservation
miss Akunina [59]

Answer:

a) 0.109375 = 0.109 to 3 d.p

b) 1.00 to 3 d.p

Step-by-step explanation:

Probability of someone that made a reservation not showing up = 50% = 0.5

Probability of someone that made a reservation showing up = 1 - 0.5 = 0.5

a) If six reservations are made, what is the probability that at least one individual with a reservation cannot be accommodated on the trip?

For this to happen, 5 or 6 people have to show up since the limousine can accommodate a maximum of 4 people

Let P(X=x) represent x people showing up

probability that at least one individual with a reservation cannot be accommodated on the trip = P(X = 5) + P(X = 6)

P(X = x) can be evaluated using binomial distribution formula

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = 6

x = Number of successes required = 5 or 6

p = probability of success = 0.5

q = probability of failure = 0.5

P(X = 5) = ⁶C₅ (0.5)⁵ (0.5)⁶⁻⁵ = 6(0.5)⁶ = 0.09375

P(X = 6) = ⁶C₆ (0.5)⁶ (0.5)⁶⁻⁶ = 1(0.5)⁶ = 0.015625

P(X=5) + P(X=6) = 0.09375 + 0.015625 = 0.109375

b) If six reservations are made, what is the expected number of available places when the limousine departs?

Probability of one person not showing up after reservation of a seat = 0.5

Expected number of people that do not show up = E(X) = Σ xᵢpᵢ

where xᵢ = each independent person,

pᵢ = probability of each independent person not showing up.

E(X) = 6(1×0.5) = 3

If 3 people do not show up, it means 3 people show up and the number of unoccupied seats in a 4-seater limousine = 4 - 3 = 1

So, expected number of unoccupied seats = 1

5 0
3 years ago
Whoever is first and gives the best explanation on how you did it ​
nikklg [1K]

Answer:

80

Step-by-step explanation:

8+6^2×2

8 + 36 × 2

8+72

80

6 0
3 years ago
Read 2 more answers
What is the standard form of this polynomial: 7 - x³ + 2x - 4x²?
Nadya [2.5K]

Answer:

−x^3−4x^2+2x+7

Step-by-step explanation:

3 0
2 years ago
Six friends attend a party. They form pairs for a game. How many different pairs are possible?
Leona [35]

Pairs, in this case, relates to a group of 2 or more. We have 6 friends. Let's call them A,B,C,D,E,F. This will allow us to make a [some sort of] combination tree:

1. ABC against DEF

2. ABD against CEF

3. ABE against CDF

4. ABF against CDE

5. ACD against BFE

6. ACE against BDF

7. ACF against BDE

8. ADE against BCF

9. ADF against BCE

10. AEF against BCD

I believe there are 12 combinations... I just can't think of the last 2 though.

5 0
3 years ago
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