I think it’s q12 or C hope this helped
Answer:
the original volume is lesser than the new volume by 242.47 in³
Step-by-step explanation:
Volume of a cone is;
V = ⅓πr²h
Where;
r is radius
h is height
For the original chamber;
r = 5.7/2 = 2.85 inches
h = 12 inches
Volume of this original chamber is;
V_orig = ⅓ × π × 2.85² × 12
V_orig = 102.02 in³
In the new design, the chamber is scaled by a factor of 1.5.
Thus;
r_new = 2.85 × 1.5 = 4.275 inches
h_new = 12 × 1.5 = 18 inches
V_new = ⅓ × π × 4.275² × 18
V_new = 344.49 inch³
V_new - V_orig = 344.49 - 102.02 =
Thus, the original volume is lesser than the new volume by 242.47 in³
Answer:
T=-20
Step-by-step explanation:
first get rid of the 7
1. T/4=-5
then multiply by 4 to isolate T
2. T=-20
Are there multiple choice options??
The rule of distributive property allows you to rewrite xa + xb as x (a + b).
So if x = 2, a = 3 and b = 4, xa + xb = x(a + b)
(2 * 3) + (2 * 4) = 2 (3 + 4)
6 + 8 = 14
14 = 14
...and so on. You may try it yourself with different variations.
Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.
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