Question

Point X is located at (2, -6) and point z is located at (0,5) find the y value that is located 1/5 the distance from point x to point z
A. -3.6

B. -3.8

C. -4

D. -4.2

Answer 1

To go from point X to point Z, the y value starts at -6 and turns into 5. So we go from y = -6 to y = 5. This is a distance of 11 units. You can count out the vertical spaces or subtract to get |-6-5| = |-11| = 11, or you can do |5-(-6)| = |5+6| = |11| = 11.

Divide this vertical distance (11) by 5, which is the same as multiplying by 1/5 = 0.2, and you get 11/5 = 11*(1/5) = 11*0.2 = 2.2

The last step is to then add that result (2.2) to the y coordinate of x so we move 1/5th of the way along the line XZ, so we'll have -6+2.2 = -3.8

Answer: Choice B) -3.8