Given t=gh/10
gh=10t
h=10t/g
Answer:
x=-8
Step-by-step explanation:
2x+7 = -x-1
x+7=-1
x=-8
<h3>Given</h3>
- a cone of height 0.4 m and diameter 0.3 m
- filling at the rate 0.004 m³/s
- fill height of 0.2 m at the time of interest
<h3>Find</h3>
- the rate of change of fill height at the time of interest
<h3>Solution</h3>
The cone is filled to half its depth at the time of interest, so the surface area of the filled portion will be (1/2)² times the surface area of the top of the cone. The filled portion has an area of
... A = (1/4)(π/4)d² = (π/16)(0.3 m)² = 0.09π/16 m²
This area multiplied by the rate of change of fill height (dh/dt) will give the rate of change of volume.
... (0.09π/16 m²)×dh/dt = dV/dt = 0.004 m³/s
Dividing by the coefficient of dh/dt, we get
... dh/dt = 0.004·16/(0.09π) m/s
... dh/dt = 32/(45π) m/s ≈ 0.22635 m/s
_____
You can also write an equation for the filled volume in terms of the filled height, then differentiate and solve for dh/dt. When you do, you find the relation between rates of change of height and area are as described above. We have taken a "shortcut" based on the knowledge gained from solving it this way. (No arithmetic operations are saved. We only avoid the process of taking the derivative.)
Note that the cone dimensions mean the radius is 3/8 of the height.
V = (1/3)πr²h = (1/3)π(3/8·h)²·h = 3π/64·h³
dV/dt = 9π/64·h²·dh/dt
.004 = 9π/64·0.2²·dh/dt . . . substitute the given values
dh/dt = .004·64/(.04·9·π) = 32/(45π)
Any 4 sides polygon has total of 360 degree
therefore adding p all angles you got 268x +100= 360
minus 100 on both side 268x= 260
divide 268 on both side you got x around .97
therefore angle C is around 99.25.....closest answer is D 100
hope this help
The ex- suffix often correlates a word to mean "outside", while the in- suffix often correlates a word to mean "inside". An exterior angle of a polygon would mean "an angle outside of a polygon". An interior angle of a polygon would mean "an angle inside of a polygon". Three exterior angles of this polygon would be angle B, angle D, and angle A. This is because these angles are outside of the polygon due to the extending lines from the shape. Two interior angles of this polygon would be angle 6 and angle 8 (explanation was given when I first began answering this question). Angle 9 would be exterior since it is outside of the polygon. Two exterior angles of the polygon that are congruent are angle D and angle 9, since they are both 90 degrees (right angles).