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viva [34]
3 years ago
15

Quadrilateral RSTU is a parallelogram. What must be the value of x?

Mathematics
1 answer:
Ierofanga [76]3 years ago
5 0
Well, that's pretty easy. The main thing you need to know to solve this task is that since the o<span>pposite sides of a parallelogram are congruent,sides RS = TU. 
Then we can find the value of x : 
</span>2x+5 = x + 16. &#10;&#10;x = 11
<span>I am sure that helps!</span>
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Plz help me with dis its one question
tatiyna

Answer:

Alix does. See below.

Step-by-step explanation:

Givens

<em><u>Jenny</u></em>

  • b1 = 90 cm
  • b2 = 80 cm
  • height = 23 cm

<em><u>Alex</u></em>

  • b1 = 90 cm
  • b2 = 70 cm
  • height = 27 cm

Formula

For both territories the answer is based on the formula

  • Area = (b1 + b2)*h/2

Solution

<em><u>Jenny</u></em>

  • Area = (90 + 80)23/2
  • Area = 170 * 23 / 2
  • Area = 85 * 23
  • Area = 1955 units.

<em><u>Alex</u></em>

  • Area = (70 + 90)*27/2
  • Area = 160*27 / 2
  • Area = 80* 27
  • Area = 2160

Alix does by 205 cm

7 0
3 years ago
The table below shows the relationship between m and p, where the independent variable is p.
scoray [572]

Answer:

C

Step-by-step explanation:

P is an independent variable, therefore making M a dependent variable.

B and D are not it.

When plugging in P in choice A, M has a different answer than in the list.

A is not it.

When pluggin in P in choice C, M has the same answers as in the list.

C is the answer

5 0
2 years ago
In the year 2003, a company made $6.8 million in profit. For each consecutive year after that, their profit increased by 13%. Ho
LenKa [72]

Answer:

$7.7 million

Step-by-step explanation:

Given: $6.8 million profit made by company.

           13% increase in profit every year.

Now, finding the company´s profit in the year of 2006.

As we know there is 13% increase in profit.

∴ Profit increase= \frac{13}{100} \times 6.8= \$ 0.884

Next adding company´s profit with increase in profit to get profit in the year 2006.

∴ 6.8+0.884= \$ 7.684 ≅ $7.7

The company´s profit in the year 2006 is $7.7 million.

6 0
2 years ago
Indicate the equation of the given line in standard form. Show all your work for full credit. the line containing the median of
alukav5142 [94]

Answer:

* The equation of the median of the trapezoid is 10x + 6y = 39

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line whose end points are (x1 , y1) , (x2 , y2) is

  m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The mid point of the line whose end point are (x1 , y1) , (x2 , y2) is

  (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

- The standard form of the linear equation is Ax + BC = C, where

  A , B , C are integers and A , B ≠ 0

- The median of a trapezoid is a segment that joins the midpoints of

 the nonparallel sides

- It has two properties:

# It is parallel to both bases

# Its length equals half the sum of the base lengths

* Lets solve the problem

- The trapezoid has vertices R (-1 , 5) , S (! , 8) , T (7 , -2) , U (2 , 0)

- Lets find the slope of the 4 sides two find which of them are the

 parallel bases and which of them are the non-parallel bases

# The side RS

∵ m_{RS}=\frac{8-5}{1 - (-1)}=\frac{3}{2}

# The side ST

∵ m_{ST}=\frac{-2-8}{7-1}=\frac{-10}{6}=\frac{-5}{3}

# The side TU

∵ m_{TU}=\frac{0-(-2)}{2-7}=\frac{2}{-5}=\frac{-2}{5}

# The side UR

∵ m_{UR}=\frac{5-0}{-1-2}=\frac{5}{-3}=\frac{-5}{3}

∵ The slope of ST = the slop UR

∴ ST// UR

∴ The parallel bases are ST and UR

∴ The nonparallel sides are RS and TU

- Lets find the midpoint of RS and TU to find the equation of the

 median of the trapezoid

∵ The median of a trapezoid is a segment that joins the midpoints of

   the nonparallel sides

∵ The midpoint of RS = (\frac{-1+1}{2},\frac{5+8}{2})=(0,\frac{13}{2})

∵ The median is parallel to both bases

∴ The slope of the median equal the slopes of the parallel bases = -5/3

∵ The form of the equation of a line is y = mx + c

∴ The equation of the median is y = -5/3 x + c

- To find c substitute x , y in the equation by the coordinates of the

  midpoint of RS  

∵ The mid point of Rs is (0 , 13/2)

∴ 13/2 = -5/3 (0) + c

∴ 13/2 = c

∴ The equation of the median is y = -5/3 x + 13/2

- Multiply the two sides by 6 to cancel the denominator

∴ The equation of the median is 6y = -10x + 39

- Add 10x to both sides

∴ The equation of the median is 10x + 6y = 39

* The equation of the median of the trapezoid is 10x + 6y = 39

7 0
3 years ago
Convert 35 mi/h to km/h
notsponge [240]
<span>Convert 35 mi/h to km/h

</span>35  \dfrac{mi}{h}\to  \dfrac{km}{h}\qquad \qquad 1 mi= 1,60934 \\  \\  \\ 35  \dfrac{mi}{h}* \dfrac{1,60934\ km}{1\ mi}= \boxed{  56,3269\dfrac{km}{h} }<span>
</span>
3 0
3 years ago
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