$\bf \stackrel{x-intercept}{(\stackrel{x_1}{2}~,~\stackrel{y_1}{0})}\qquad \stackrel{y-intercept}{(\stackrel{x_2}{0}~,~\stackrel{y_2}{6})} \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-0}{0-2}\implies \cfrac{6}{-2}\implies -3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=-3(x-2)\implies y=-3x+6$

5 0

2 years ago

BEST ANSWER EARNS BRAINLIEST!

Lady bird [3.3K]

Please mark brainliest 3 more to rankup.

so is how I would solve this is one corner at a time. Since these are all triangles you will solve the area of a corner and divide it by 2. Then you will have the area of a corner.

(7.5 x 5) /2= 18.75
(7.5 x 14) /2=52.5
Mirror this on the other side because they are the same on the other side and then add them all together

(18.75 x 2) + (52.5 x 2) = 142.5

Answer is A
142.5

3 0

2 years ago