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4 years ago

How can I determine the value of x that will make the expression a real √x-1

1 answer:

6 0

The content of the square root must be greater than or equal to zero. Determine the conditions on x that make this true.

As written, you require
.. x ≥ 0

If you intend
.. √(x -1) ∈ ℝ
Then
.. x -1 ≥ 0
Solve this inequality by adding 1.
.. x ≥ 1

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3 years ago

What is the y-intercept of the line represented by y = 4x?

alexandr402 [8]

0, there is no y-intecept.
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4 years ago

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4 years ago

6-7(x+1)= -3(2-x)<br> How do you solve this?

kicyunya [14]

<h3><u>Explanation</u></h3>

Given the equation.

$6 - 7(x + 1) = - 3(2 - x)$

Distribute/Simplify

$6 - 7x - 7 = - 6 + 3x \\ - 1 - 7x = - 6 + 3x$

Solve the equation for x-term by making x as the subject.

$- 1 + 6 = 7x + 3x \\ 5 = 10x \\ \frac{5}{10} = x \\ \frac{1}{2} = x$

Answer Check by substituting the value of x in the equation.

$6 - 7( \frac{1}{2} ) - 7 = - 6 + 3( \frac{1}{2} ) \\ 6 - \frac{7}{2} - 7 = - 6 + \frac{3}{2} \Longrightarrow \sf{You \: \: can \: \: change \: \: sides \: \: to \: \: make \: \: it \: \: easier} \\ 6 - 7 + 6 = \frac{7}{2} + \frac{3}{2} \\ 5 = \frac{10}{2} \\ 5 = 5 \: \green{ \checkmark}$

The equation is true for x = 1/2.

<h3><u>Answer</u></h3>

<u> $\large \boxed{x = \frac{1}{2} } \: \: \: \: \green{ \checkmark}$ </u>

7 0

3 years ago