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mariarad [96]
3 years ago
8

How can I determine the value of x that will make the expression a real √x-1

Mathematics
1 answer:
Sholpan [36]3 years ago
6 0
The content of the square root must be greater than or equal to zero. Determine the conditions on x that make this true.

As written, you require
.. x ≥ 0

If you intend
.. √(x -1) ∈ ℝ
Then
.. x -1 ≥ 0
Solve this inequality by adding 1.
.. x ≥ 1
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Answer:

2/4

Step-by-step explanation:

Rise over run. you go up 2 and right 4

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For the square find coordinates for B without using any new variables
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3 years ago
#1. Which is equal to z3 8? A. (z - 2)(z^2 - 2z - 4). B. (z + 2)(z^2 - 2z + 4) C.(z - 2)(z^2+ 2z + 4). D. (z + 2)(z^2+ 2z - 4) #
tankabanditka [31]
#1. B
<span>(z * z^2 + z * 2z + z * 4) – (-2 *z^2 – (-2) 2z – (-2) 4)
Z^3 + 2z^2 + 4z – 2z^2 -4z – 8
Z^3 + 2z^2 – 2z^2 + 4z – 4z – 8
Z^3 - 8
</span>
#2 and #3. D
<span>(x + y)(x + 2)
x^2 + 2x + yx + 2y
</span>
#4. D.
<span>(x - 7)(x + 7)(x- 2)
x^2 + 7x – 7x -49
x^2 + x – 49
x^2 -49
(x^2 – 49 ) (x – 2)
x^3 – 2x^2 – 49x + 98
</span>
#5. C
(y - 4) = 0
y = 4
(x + 3)= 0
x = -3

#6. A and B
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3 years ago
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S_A_V [24]

Answer:

8y=8 or 4y=-4

Step-by-step explanation:

1.)-2(x+3y=-1)

   2x+2y=6

2.)-2x+6y=2

     2x+2y=6

3.)6y=2  

   2y+6

4.)8y=8 (If adding) or 4y=-4 (If subtracting)

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