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Harlamova29_29 [7]
3 years ago
11

What is the slope of this line?

Mathematics
1 answer:
professor190 [17]3 years ago
7 0

y=2/3x-3

Hope it helps a bunch

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Fred is making a bouquet of carnationsand roses. The carnations cost $5.25 in all. The roses are $1.68 each. If Fred spent $18.6
kotegsom [21]

Answer:

8 roses

Step-by-step explanation:

18.69-5.25=13.44

13.44÷1.68=8 Hope this helps.

4 0
3 years ago
Read 2 more answers
What equation represents a circle whose center is located at (-6,2) and whose radius is 10 units?
Anna [14]
One of the equations for a circle is (x - h)² + (y - k)² = r² where (h, k) are the center and r is the radius.
So after substitution:
(x + 6)² + (y - 2)² = 100

Notice the equation has the opposite of h and k and 100 is the result of squaring 10.
3 0
3 years ago
Is f(x)=5x^2+6x^3 a polynomial function​
anastassius [24]
Polynomials are expressions whose exponents are non-negative integers and the coefficients are real numbers. The leading term is the term with the highest power. The coefficient of the leading term is the leading coefficient. The power of x in the leading term is called the degree of the polynomial! Here are some examples of polynomials:
Degree Name Example
0 constant 11
1 linear 4x + 7
2 quadratic 3x2 + 4x + 5
3 cubic 4x3 + 3x + 7
4 quartic 3x4 + 2x2 + 4
5 quintic x5 + 3x + 1
Any value of x such that P(x) = 0 is a root of the equation and a zero of the function.
Review of synthetic substitution
To use synthetic substitution, do the following:
1) Write the polynomial in descending order.
2) Make sure any missing terms are replaced with zero!
3) Bring down the leading coefficient.
4) Multiply by the divisor and add to the next term.
5) Repeat the process until the last coefficient is reached.

Example
Use synthetic division to find P(2) for P(x) = 2x3 - 9x2 + 27
2| 2 -9 0 27
4 -10 -20
2 -5 -10 7 The value of P(2) = 7, the last number!!
Sample Problems
1) State whether each is a polynomial function. If yes, find the degree and the zeros.
Problem Polynomial? Degree zeros
a) f(x) = 5 - 4x yes 1 5/4
b) f(x) = 3x2 - 6x yes 2 0, 2
c) f(x) = x - 3/x no
d) f(x) = 18 yes 0 none
e) f(x) = (x-3)/(x+2) no
2) Use synthetic substitution to find P(3) for each function:
a) P(x) = 4x3 - 5x2 + 3
3| 4 -5 0 3
12 21 63
4 7 21 66
Therefore, P(3) = 66

b) P(x) = 3x4 + 2x3 - 5x - 2

3| 3 2 0 -5 -2
9 33 99 282
3 11 33 94 280
Therefore, P(3) = 280


3) If 4 is a zero of f(x) = 3x3 + kx - 2, find the value of k.
Since 4 is a zero, the value of f(4) = 0. Use synthetic substitution.
4| 3 0 k -2
12 48 192 + 4k
3 12 48 + k 190 + 4k
Now 190 + 4k = 0, solve for k
4k = -190
k = -190/4 = -47.5
3 0
4 years ago
Solve this equations using substitutions<br> -2x+6y=1
gtnhenbr [62]

Answer:

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
F(1) = 0<br> f(n) = f(n-1)+2<br> Find an explicit formula for f(n).<br> f(n) =
Anna35 [415]
The answer is if f is 1
3 0
3 years ago
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