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puteri [66]
3 years ago
11

The length of a side of an equilateral triangle is 40cm. what is the length of the altitude of the triangle?

Mathematics
1 answer:
podryga [215]3 years ago
4 0

Answer:

20√3 cm

Step-by-step explanation:

Altitude of an equilateral triangle splits it into 2 equal right triangles, it bisects the base and the angle opposite to the base.

<u>Let the altitude be x. Then as per Pythagorean theorem:</u>

  • x² = 40² - (40/2)²
  • x²= 1600 -400
  • x²= 1200
  • x= √1200
  • x= 20√3 cm

<u>Correct choice is</u> the second one

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Read 2 more answers
Find the sum that amounts to Rs 9,144 in 3 years at 9% per year simple interest.​
Hunter-Best [27]

Given:

Amount = Rs. 9,144

Time = 3 years.

Rate of simple interest = 9%

To find:

The principal value.

Solution:

The formula for simple interest is:

I=\dfrac{P\times r\times t}{100}

Where, P is principal, r is the simple rate of interest, and t is the number of years.

Putting r=9,t=3 in the above formula, we get

I=\dfrac{P\times 9\times 3}{100}

I=\dfrac{27P}{100}

I=0.27P

We know that,

\text{Amount}=\text{Principal + Interest}

9144=P+0.27P

9144=1.27P

Divide both sides by 1.27, we get

\dfrac{9144}{1.27}=P

7200=P

Therefore, the principal value is Rs. 7200.

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3 years ago
11. Let X denote the amount of time a book on two-hour reserve is actually checked out, and suppose the cdf is F(x) 5 5 0 x , 0
NISA [10]

Question not properly presented

Let X denote the amount of time a book on two-hour reserve is actually checked out, and suppose the cdf is F(x)

0 ------ x<0

x²/25 ---- 0 ≤ x ≤ 5

1 ----- 5 ≤ x

Use the cdf to obtain the following.

(a) Calculate P(X ≤ 4).

(b) Calculate P(3.5 ≤ X ≤ 4).

(c) Calculate P(X > 4.5)

(d) What is the median checkout duration, μ?

e. Obtain the density function f (x).

f. Calculate E(X).

Answer:

a. P(X ≤ 4) = 16/25

b. P(3.5 ≤ X ≤ 4) = 3.75/25

c. P(4.5 ≤ X ≤ 5) = 4.75/25

d. μ = 3.5

e. f(x) = 2x/25 for 0≤x≤2/5

f. E(x) = 16/9375

Step-by-step explanation:

a. Calculate P(X ≤ 4).

Given that the cdf, F(x) = x²/25 for 0 ≤ x ≤ 5

So, we have

P(X ≤ 4) = F(x) {0,4}

P(X ≤ 4) = x²/25 {0,4}

P(X ≤ 4) = 4²/25

P(X ≤ 4) = 16/25

b. Calculate P(3.5 ≤ X ≤ 4).

Given that the cdf, F(x) = x²/25 for 0 ≤ x ≤ 5

So, we have

P(3.5 ≤ X ≤ 4) = F(x) {3.5,4}

P(3.5 ≤ X ≤ 4) = x²/25 {3.5,4}

P(3.5 ≤ X ≤ 4) = 4²/25 - 3.5²/25

P(3.5 ≤ X ≤ 4) = 16/25 - 12.25/25

P(3.5 ≤ X ≤ 4) = 3.75/25

(c) Calculate P(X > 4.5).

Given that the cdf, F(x) = x²/25 for 0 ≤ x ≤ 5

So, we have

P(4.5 ≤ X ≤ 5) = F(x) {4.5,5}

P(4.5 ≤ X ≤ 5) = x²/25 {4.5,5}

P(4.5 ≤ X ≤ 5)) = 5²/25 - 4.5²/25

P(4.5 ≤ X ≤ 5) = 25/25 - 20.25/25

P(4.5 ≤ X ≤ 5) = 4.75/25

(d) What is the median checkout duration, μ?

Median is calculated as follows;

∫f(x) dx {-∝,μ} = ½

This implies

F(x) {-∝,μ} = ½

where F(x) = x²/25 for 0 ≤ x ≤ 5

F(x) {-∝,μ} = ½ becomes

x²/25 {0,μ} = ½

μ² = ½ * 25

μ² = 12.5

μ = √12.5

μ = 3.5

e. Calculating density function f (x).

If F(x) = ∫f(x) dx

Then f(x) = d/dx (F(x))

where F(x) = x²/25 for 0 ≤ x ≤ 5

f(x) = d/dx(x²/25)

f(x) = 2x/25

When

F(x) = 0, f(x) = 2(0)/25 = 0

When

F(x) = 5, f(x) = 2(5)/25 = 2/5

f(x) = 2x/25 for 0≤x≤2/5

f. Calculating E(X).

E(x) = ∫xf(x) dx, 0,2/5

E(x) = ∫x * 2x/25 dx, 0,2/5

E(x) = 2∫x ²/25 dx, 0,2/5

E(x) = 2x³/75 , 0,2/5

E(x) = 2(2/5)³/75

E(x) = 16/9375

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3 years ago
Which graph best represents the relationship between time and the average mass?
natita [175]
The second graph or the letter B
3 0
3 years ago
An executive committee consists of 15 members: 7 men &amp; 8 women. 5 members are selected at random to attend a meeting in Hawa
asambeis [7]

Answer:

1.8%

Step-by-step explanation:

(8c5 * 7c0)/15c5

= 0.018

This is the answer which I get when I solve this... cross check the calculations once.

3 0
3 years ago
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