2x + 7 + 6x - x what is equivalent to

mash [69]

Answer:

It will cost $36.38 to travel 8.9 miles.

Step-by-step explanation:

In order to get how much it will cost to travel 8.9 miles, you need to first set up a linear equation (in slope-intercept form, which is $y=mx+b$ ). You can do this with what the problem has given us. Since there's a flat fee of $3, that is the y-intercept or the $b$ slope-intercept form. Then there is $3.75 added for every additional mile traveled, making it the slope or the $m$ in slope-intercept form. That makes the equation look like:

$y=3.75x+3$

The $x$ in that equation represents how far you traveled. Therefore in order to find out 8.9 miles, plug in 8.9 for $x$ .

$y=3.75(8.9)+3$

Simply solve the equation and you will have how much it will cost to travel 8.9 miles.

$y=33.375+3$

Now add the like terms:

$y=36.375$

Since it needs to be rounded to the nearest cent, you will round to the nearest tenth:

$y=36.38$

Therefore, it will cost $36.38 to travel 8.9 miles.

6 0

3 years ago

HELPP FASTT!!

joja [24]

Answer:

Those questions are from a story or something like that, so if you dont send the story we can not help you :(

8 0

3 years ago

Read 2 more answers

Will give brainliest answer

makvit [3.9K]

Answer:

$28 . 26cm$

Step-by-step explanation:

First find the radius

$d = 2r \\ 9 = 2r \\ \frac{9}{2} = \frac{2r}{2} \\ r = 4.5$

Now find the CIRCUMFERENCE

$c = 2\pi \: r \\ = 2 \times \pi \times 4.5 \\ = 9 \times \pi \\ = 28.26$

5 0

3 years ago

A sample of 125 pieces of yarn had mean breaking strength 6.1 N and standard deviation 0.7 N. A new batch of yarn was made, usin

AlexFokin [52]

Answer:

The 90% confidence interval for the difference in mean breaking strength between the two types of yarn is (0.08N, 0.52N).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction of normal variables:

When we subtract two normal variables, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

A sample of 125 pieces of yarn had mean breaking strength 6.1 N and standard deviation 0.7 N.

This means that $\mu_1 = 6.1, s_1 = \frac{0.7}{\sqrt{125}} = 0.0626$

In a sample of 75 pieces of yarn from the new batch, the mean breaking strength was 5.8 N and the standard deviation was 1.0 N.

This means that $\mu_2 = 5.8, s_2 = \frac{1}{\sqrt{75}} = 0.1155$

Distribution of the difference:

$\mu = \mu_1 - \mu_2 = 6.1 - 5.8 = 0.3$

$s = \sqrt{s_1^2+s_2^2} = \sqrt{0.0626^2+0.1155^2} = 0.1314$

Confidence interval:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.645.

Now, find the margin of error M as such

$M = zs$

$M = 1.645*0.1314 = 0.22$

The lower end of the interval is the sample mean subtracted by M. So it is 0.3 - 0.22 = 0.08N

The upper end of the interval is the sample mean added to M. So it is 0.3 + 0.22 = 0.52N

The 90% confidence interval for the difference in mean breaking strength between the two types of yarn is (0.08N, 0.52N).

3 0

3 years ago

explain the place value relationship when the same two digits are next to each other in a multidigit number

alisha [4.7K]

For example, the value of digit 3 in 5833

5833 = 5000 + 800 + 30 + 3

The digits 3 in 5833 has value of 30 and 3
One value is ten times the other

Another example, the value of digit 6 in 586645

586645 = 500000 + 80000 + 6000 + 600 + 40 + 5

The digits 6 in 586645 is 6000 and 600
One digit is 10 times the other

We can make a conclusion that the place value relationship when the same two digits are next to each other is one digit will always be 10 times the other digit.

3 0

3 years ago