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2 years ago

Which best describes the relationship between the line that passes through the points (-6,5) and (-

Mathematics

1 answer:

natita [175]2 years ago

3 0

Answer:

Slope passes through (-6, 5) and (-2, 7)

$m_1=\frac{y_2-y_1}{x_2-x_1} =m_1=\frac{7-5}{-2+6}$

$m_1=\frac{2}{4} =\frac{1}{2}$

Slope passes through (4, 2) and (6, 6)

$m_2=\frac{6-2}{6-4}$

$\frac{4}{2} =2$

$m_1\times m_2 \neq -1$ $m_1\neq m_2$

Answer:- A) neither perpendicular nor parallel.

OAmalOHopeO

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Solve the inequality. -1/2a < 6

rewona [7]

Answer:

a > -12

Step-by-step explanation:

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2 years ago

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What is the quotient? Negative StartFraction 3 over 8 EndFraction divided by negative one-fourth

anyanavicka [17]

Answer:

$\dfrac{3}{2}$

Step-by-step explanation:

We are given 2 fractions.

1st fraction is Negative StartFraction 3 over 8

i.e.

$-\dfrac{3}{8}$

2nd fraction is negative one-fourth

i.e.

$-\dfrac{1}{4}$

We have to find the quotient when 1st fraction is divided by 2nd fraction.

Definition of quotient is given as:

Quotient is the result obtained when one number is divided by other number.

$-\dfrac{3}{8} \div -\dfrac{1}{4} \text{ is to be calculated.}$

$\div$ is converted to $\times$ and the 2nd fraction is reversed i.e.

if the fraction is $\frac{p}{q}$ it becomes $\frac{q}{p}$ and the sign $\div$ is changed to $\times$ .

Solving above:

$-\dfrac{3}{8} \times -\dfrac{4}{1}\\ \text {Multiplication/Division of 2 negative number gives a positive number}\\\Rightarrow \dfrac{3}{2}$

So, the quotient is $\frac{3}{2}$ .

6 0

2 years ago

What is the equation in point slope form of the line that passes through the point (2,6) and has slope of 5?

sleet_krkn [62]

Firstly, you can use the slope and the first point to find a second point:
2 + 1 = x2 and 6 + 5 = y2 because the slope is 5/1.
Next you can write the equation in point-slope form (remember point-slope form is y - y1 = m(x - x1):
y - 11 = 5(x - 3)
Another equation would be B because B is the correct equation if you choose 2 as x2 and 6 as y2.
Hope this helps!

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2 years ago

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Multiplying Vertically:

Ad libitum [116K]

Answer:

6. Find the product for both sets of polynomials below by multiplying vertically. (4 points: 2 points for each product)

4x^4 - 4x^3 - 16x^2 + 16x

7. Are the two products the same when you multiply them vertically? (1 point)

Yes, the two products are the same when you multiply them.

Making a Decision:

8. Who was right, Emily or Zach? Are the products the same with the three different methods of multiplication? (1 point)

Emily was right, the products are the same with all three different methods of multiplication.

9. Which of these three methods is your preferred method for multiplying polynomials? Why? (1 point)

I prefer the table method because it is easier to understand what is going on, know where and what to do, and it is nicely and neatly laid out in front of me.

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2 years ago

The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of

Ivenika [448]

Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

$AV = \frac{y(t2) - y(t1)}{t2 - t1}$

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

$AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6$

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii) t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

$AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8$

So the average speed is -128.9 ft/s

iii) t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

$AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16$

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

3 0

2 years ago