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3 years ago

Find -71+(-146)+(-32) please help me answer this

Mathematics

2 answers:

navik [9.2K]3 years ago

5 0

-146+(-103)= - 249

I hope helps this

Sergio039 [100]3 years ago

3 0

The answer is -249. Hope this helps! Message me with any questions :)

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Name one whole number, one integer, one rational number, and one irrational number. Do not use the same number twice.

AURORKA [14]

Answer:

10, 5, .75, π

Step-by-step explanation:

5 0

3 years ago

Find AC please, help is very much appreciated.

fenix001 [56]

Answer:

AC ≈ 67.9

Step-by-step explanation:

15² = 9 (3x + 1 + 9)

225 = 9 (3x + 10)

225 = 27x + 90

135 = 27x

x ≈ 19.29

AC = (3x + 1 + 9)

AC = 3 (19.2857...) + 1 + 9

AC = 57.857... + 1 + 9

AC = 57.857... + 10

AC ≈ 67.9

4 0

2 years ago

Half x + 10 equals quarter x + 54

IgorLugansk [536]

½(x+10) = ¼(x+54)
Solving it

x/2 + 5 = x/4 + 13.5
x/2 - x/4 = 13.5 - 5
x/4 = 8.5
x = 8.5 × 4 = 34

5 0

3 years ago

Find the coordinates of point B along a directed line segment from A(3,4) and

andreev551 [17]

We have been given two points. $A(3,4)$ and $C(3,9)$ . We are asked to find the point B such that it divides line segment AC so that the ratio of AB to BC is 4:1.

We will use segment formula to solve our given problem.

When a point P divides segment any segment internally in the ratio $m:n$ , then coordinates of point P are:

$[\right x=\frac{mx_2+nx_1}{m+n},y=\frac{my_2+ny_1}{m+n}\left]$

$(x_1,y_1)=(3,4)$ and $(x_2,y_2)=(3,9)$ .

$m=4,n=1$

Upon substituting our given information in above formula, we will get:

$[\right x=\frac{4(3)+1(3)}{4+1},y=\frac{4(9)+1(4)}{4+1}\left]$

$[\right x=\frac{12+3}{5},y=\frac{36+4}{5}\left]$

$[\right x=\frac{15}{5},y=\frac{40}{5}\left]$

$[\right x=3,y=8\left]$

Therefore, the coordinates of point B would be $(3,8)$ .

8 0

3 years ago

Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).

Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5$

well then therefore

$\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}$

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

$(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}$

6 0

2 years ago