I believe so. (TRUE). a square has all equal sides so if the figure is just alike, its a reg quad.
Answer:
y = x*sqrt(Cx - 1)
Step-by-step explanation:
Given:
dy / dx = (x^2 + 5y^2) / 2xy
Find:
Solve the given ODE by using appropriate substitution.
Solution:
- Rewrite the given ODE:
dy/dx = 0.5(x/y) + 2.5(y/x)
- use substitution y = x*v(x)
dy/dx = v + x*dv/dx
- Combine the two equations:
v + x*dv/dx = 0.5*(1/v) + 2.5*v
x*dv/dx = 0.5*(1/v) + 1.5*v
x*dv/dx = (v^2 + 1) / 2v
-Separate variables:
(2v.dv / (v^2 + 1) = dx / x
- Integrate both sides:
Ln (v^2 + 1) = Ln(x) + C
v^2 + 1 = Cx
v = sqrt(Cx - 1)
- Back substitution:
(y/x) = sqrt(Cx - 1)
y = x*sqrt(Cx - 1)
Expression — 6+2.05p
Evaluation— 6+2.05(25)
To solve for X you must get x by itself so let's get started
-4x+13=6x-7
subtract 13 from both sides
-4x=6x-20
subtract 6x from both sides
-10x=-20
divide both sides by -10
x=2
to check if this is correct plug in x into original equation
-4 (2)+13=6 (2)-7
-8+13=12-7
5=5
answer x=2 holds true :)