The correct answers are everything bu the second one
![\bf \begin{array}{clclll} -6&+&6\sqrt{3}\ i\\ \uparrow &&\uparrow \\ a&&b \end{array}\qquad \begin{cases} r=\sqrt{a^2+b^2}\\ \theta =tan^{-1}\left( \frac{b}{a} \right) \end{cases}\qquad r[cos(\theta )+i\ sin(\theta )]\\\\ -------------------------------\\\\](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bclclll%7D%0A-6%26%2B%266%5Csqrt%7B3%7D%5C%20i%5C%5C%0A%5Cuparrow%20%26%26%5Cuparrow%20%5C%5C%0Aa%26%26b%0A%5Cend%7Barray%7D%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0Ar%3D%5Csqrt%7Ba%5E2%2Bb%5E2%7D%5C%5C%0A%5Ctheta%20%3Dtan%5E%7B-1%7D%5Cleft%28%20%5Cfrac%7Bb%7D%7Ba%7D%20%5Cright%29%0A%5Cend%7Bcases%7D%5Cqquad%20r%5Bcos%28%5Ctheta%20%29%2Bi%5C%20sin%28%5Ctheta%20%29%5D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C)

now, notice, there are two valid angles for such a tangent, however, if we look at the complex pair, the "a" is negative and the "b" is positive, that means, "x" is negative and "y" is positive, and that only occurs in the 2nd quadrant, so the angle is in the second quadrant, not on the fourth quadrant.
thus
You are correct. For each of the three possibilities for their second day, there are two possibilities for the third day.
The total number of possibilities is 3*2 = 6.
Answer:
Answer: Natural Numbers count physical things. They can't be negative.
The third option is correct because its fractions and decimals.
Step-by-step explanation:
Hope this helps!
Answer:
y = 2x
y = 3x - 3
Step-by-step explanation:
Hi,
<u>y = 2x</u>
<u>6 = 2(3)</u>
<u>6 = 6</u>
<u>That's a solution</u>
<u>y = 3x - 3</u>
<u>6 = 3(3) - 3</u>
<u>6 = 9 - 3</u>
<u>6 = 6</u>
<u>That's a solution</u>
Hope this helps :)