Answer:
D. Yes; the graph passes the vertical line test.
Step-by-step explanation:
→The vertical line test is when you hold something (like a pencil), straight up/vertically, and you move it from left-to-right to see if any two points repeat.
<u>→The correct answer is "D. Yes; the graph passes the vertical line test,"</u> because the x-values can't repeat, not the y-values, if the graph were to show a function. In this case, the graph passes the vertical line test.
Answer:
mark me brainliest please and its a yes
Step-by-step explanation:
The answer is 5 Bc it’s half of ten
No. 3/10 X 100/1 = 300/10 = 30.
Answer:

Step-by-step explanation:
Given the expression;
g(t) = 6 + t + t²/√t
This can be rewritten as;
g(t) = 6 + t +t²/t^1/2
g(t) = 6 + t +t^{2-1/2}
g(t) = 6 + t +t^3/2
Integrate the result

Using the formula x^{n+1}/n+1
