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fomenos
2 years ago
11

A square has a perimeter of 33 inches. write and equation that can be used to determin the length of one side , S, of the square

.
​

Mathematics
1 answer:
den301095 [7]2 years ago
5 0

Answer:

4S = 33

Step-by-step explanation:

To find the side length of one side, the perimeter has to be divided by 4 since a square has four sides.

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The tables below show two functions. For each set of data:
slamgirl [31]
The first table, representing <em>f</em>(<em>x</em>), is linear.  The data have a constant rate of change or slope:
<em />(between the first two points):  <em>m</em> = (<em>y</em>₂ - <em /><em>y</em>₁)/(<em>x</em>₂ - <em>x</em>₁) = (22-18)/(-1--2) = 4/(-1+2) = 4/1 = 4.  The rate of change  between any two points is the same:
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4 0
3 years ago
The number of unread emails in Bryan’s account is 100. This number grows by 15 unread emails a day. The function N(t)=100+15t re
miv72 [106K]

Answer:

205

Step-by-step explanation:

Given

N(t) = 100 + 15t is the equation of the relation.

We're asked to find N(7)

Taking a look at the question again and putting it side by side the equation

N(t)

N(7)

We can deduce that t = 7, and as such, solve for it in the equation given

N(7) = 100 + 15(7)

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8 0
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What is the horizontal asymptote of the function f(x)= -2x/x+1
daser333 [38]

<u>Answer:</u>

-2

<u>Step-by-step explanation:</u>

We have been given a function f(x)=\frac{-2x}{x+1} and we are asked to find the horizontal asymptote of our given function.

Recalling the rules for a horizontal asymptote:

1. If the numerator and denominator have equal degree, the horizontal asymptote will be the ratio of the leading coefficients.

2. If the polynomial of denominator has larger degree than the numerator, then the horizontal asymptote will be the x-axis or y=0.

3. If the polynomial of numerator has larger degree than denominator, then the function has no horizontal asymptote.

Here, the numerator and denominator are of the same degree. So the horizontal asymptote will be the ratio of the coefficients.

Horizontal asymptote = -\frac{2}{1} = -2

8 0
3 years ago
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