This problem can be seen as a rectangle triangle where the vertices are:
Vertice 1: home plate
Vertice 2: First base
Vertice 3: second base.
Right angle between vertice 1 and 2 and vertice 2 and 3.
Distance between each base in 90 '.
Calculating then the distance between home plate and second base we have:
d = root ((90) ^ 2 + (90) ^ 2)
d = 127.28 feets
answer:
the distance between home plate and second base is 127.28 feets
Answer:
f(1) = 16
Domain: 0 ≤ t ≤ 2
Step-by-step explanation:
Given
f(t) = -16t²+ 32t
Solving (a): f(1)
Substitute 1 for t in f(t)
f(t) =− 16t²+ 32t .
f(1) =− 16 * (1)²+ 32 * 1
f(1) = -16 * 1 + 32
f(1) = -16 + 32
f(1) = 16
Solving (b): The domain
The implication of the given parameter in (b) is that t ≤ 2.
Since t represents time, t can't be negative.
Hence, a reasonable domain is
0 ≤ t ≤ 2
Answer: 8z 8(z)
Explanation: well 8 times z is simply 8(z)I don’t really think there is another way
Answer:
2.50t + 350 = 3t + 225
Step-by-step explanation:
Let t represent the number of tickets that each class needs to sell so that the total amount raised is the same for both classes.
One class is selling tickets for $2.50 each and has already raised $350. This means that the total amount that would be raised from selling t tickets is
2.5t + 350
The other class is selling tickets for $3.00 each and has already raised $225. This means that the total amount that would be raised from selling t tickets is
3t + 225
Therefore, for the total costs to be the same, the number of tickets would be
2.5t + 350 = 3t + 225
Answer:
The 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is between 226.01 and 233.99 milligrams.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 230 - 3.99 = 226.01
The upper end of the interval is the sample mean added to M. So it is 230 + 3.99 = 233.99.
The 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is between 226.01 and 233.99 milligrams.
