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mart [117]
3 years ago
5

A computer uses 1/200 second of a secount to finish a math problem . How many math questions can the computer solve in 2 minutes

Mathematics
1 answer:
aniked [119]3 years ago
4 0

Answer: The computer can solve 24,000 math problems in 2 minutes.

Step-by-step explanation:

1.) Multiply 1 * 200, in order to get the amount of problems solved in a second, which would be 200.

2.) Multiply 200 * 60 to get the amount of problems solved in a minute, which would be 12,000.

3.) Multiply 12,000 * 2 in order to get the amount of problems solved in 2 minutes, which would be 24,000.

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Hope this helps!
4 0
3 years ago
Wht equation describes a parabola that opens up or down and whos vertex is at the point (h,v)
LUCKY_DIMON [66]

Answer:

f(x)=a(x-h)^2+k

Vertex form.

Step-by-step explanation:

You are talking about the vertex form for a parabola.

f(x)=a(x-h)^2+k tells us:

A) The vertex is (h,k).

B) Open up (if a is positive) or open down (if a is negative)

C) a also tells us how much it is vertically stretched or compressed.

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3 years ago
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Step-by-step explanation:


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3 years ago
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mamaluj [8]

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Step-by-step explanation:

4 0
3 years ago
Suppose a shipment of 400 components contains 68 defective and 332 non-defective computer components . From the shipment you tak
Alona [7]

Answer:

The standard deviation for the number of defective parts in the sample is 1.88.

Step-by-step explanation:

The sample is with replacement, which means that the trials are independent, and thus, the binomial probability distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.  

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

68 defective out of 400:

This means that p = \frac{68}{400} = 0.17

From the shipment you take a random sample of 25.

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Standard deviation for the number of defective parts in the sample:

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{25*0.17*0.83} = 1.88

The standard deviation for the number of defective parts in the sample is 1.88.

6 0
3 years ago
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