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Katyanochek1 [597]
3 years ago
13

How would i rewrite that using a single exponent

Mathematics
1 answer:
Mazyrski [523]3 years ago
6 0

Answer:

3^2 times 3^2 times 3^2 times 3^2 times 3^2 and that is 3^10

3^10 is your answer

Step-by-step explanation:

3x3=9

this 5 times

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Write an expression to 3(7 + 4g)
mafiozo [28]

Answer:

Step-by-step explanation:

21+12g

4 0
3 years ago
The ratio of girls to boys in grade 6 was 3:2 at Lincoln middle school last year. There were 60 kids in grade 6. How many in gra
olasank [31]

Answer:

40 girls 20 boys i think / guess

Step-by-step explanation:

3 0
3 years ago
What represents the inverse of the function f(x)=4x
Yuki888 [10]

Answer:

\frac{x}{4}

Step-by-step explanation:

The given function is

f(x) = 4x

As we know

f(x) = y, which implies x= f^{-1} (y)

Therefore,

y = 4x

x = \frac{y}{4}

as x= f^{-1} (y)

So,

f^{-1} (y) = \frac{y}{4}

replacing y by x in the above expression

f^{-1} (x) = \frac{x}{4}

So our inverse function is  \frac{x}{4}

4 0
3 years ago
Which one is greater? 38 0.38 or 3.8
maksim [4K]

Answer:

38 is greater

Step-by-step explanation:

3 0
3 years ago
Simplify : (√x + √y ) (√x − √y) (x + y)(x2 + y2)
Ivan

Solution, \mathrm{Expand}\::\left(\sqrt{x}+\sqrt{y}\right)\left(\sqrt{x}-\sqrt{y}\right)\left(x+y\right)\left(x^2+y^2\right):\quad :x^4-:y^4

Steps:

\mathrm{Expand}\:\left(\sqrt{x}+\sqrt{y}\right)\left(\sqrt{x}-\sqrt{y}\right):\quad x-y, =\left(x-y\right)\left(x+y\right)\left(x^2+y^2\right)

\mathrm{Expand}\:\left(x-y\right)\left(x+y\right):\quad x^2-y^2, =:\left(x^2-y^2\right)\left(x^2+y^2\right)

\mathrm{Expand}\:\left(x^2-y^2\right)\left(x^2+y^2\right):\quad x^4-y^4, =:\left(x^4-y^4\right)

\mathrm{Expand}\::\left(x^4-y^4\right):\quad :x^4-:y^4, =:x^4-:y^4

The correct answer is <u><em>x^4-y^4</em></u>

Hope this helps!!!

4 0
3 years ago
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