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Rina8888 [55]
4 years ago
13

Select each expression that shows a correct method for finding 36% of 400.

Mathematics
1 answer:
kvv77 [185]4 years ago
6 0
The answer is 136 136=36% of 400
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Dubnium-262 has a half-life of 34 s. How long will it take for 500.0 grams to
dmitriy555 [2]

Answer:

the time taken for the radioactive element to decay to 1 g is 304.8 s.

Step-by-step explanation:

Given;

half-life of the given Dubnium = 34 s

initial mass of the given Dubnium, m₀ = 500 grams

final mass of the element, mf = 1 g

The time taken for the radioactive element to decay to its final mass is calculated as follows;

1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} =  (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500})  = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s

Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.

4 0
3 years ago
What equation would you use to solve for x?
Brut [27]
I think you would use the equation 2x+1+33+90=180
3 0
3 years ago
Temperature at 9:00PM was 15° By 5 AM the temperature had dropped 20° what was the temperature at 5 PM
Arisa [49]
From 9 P.M. to 5 A.M. the temperature dropped 20°, making the rate over 8 hours, -2.5° Per Hour. By 5 A.M., the temperature is -5° since we had to do 15 - 20. From 5 AM to 5 P.M. is 12 hours so -2.5 x 12 = -30 making 30 how much the temperature dropped between 5 A.M. to 5 P.M. Finally, our last equation is -5 - 30 making -35 our answer.
4 0
3 years ago
Find the experimental probability Roll dice 1,3,3,4,4 P(1)= I’ll give brainleist
-Dominant- [34]

Answer:

\mathrm{P(1)\:}=\frac{1}{5}

Step-by-step explanation:

There are simply 5 possible values in the given set. Out of these, only one of these is the number 1. Therefore, the probability a 1 is drawn (P(1)) is \fbox{$\frac{1}{5}$}.

5 0
3 years ago
Read 2 more answers
Rewrite in simplest radical form 1 over x^(−3/6). Show each step of your process.
meriva

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\\\ ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}}

\bf \rule{34em}{0.25pt}\\\\ \cfrac{1}{x^{-\frac{3}{6}}}\implies x^{\frac{3}{6}}\implies x^{\frac{1}{2}}\implies \sqrt[2]{x^1}\implies \sqrt{x}

5 0
3 years ago
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