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morpeh [17]
3 years ago
6

Please answer quickly!

Mathematics
2 answers:
dybincka [34]3 years ago
6 0

Answer:

D.

t <= 4.

Step-by-step explanation:

15 + 3/2 t  <= 21

3/2 t <= 6

t <= 6 * 2/3

t <= 4.

Katena32 [7]3 years ago
5 0
The answer is the last one
15 + (3/2)t ≤ 12
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The mean finish time for a yearly amateur auto race was 186.32 minutes with a standard deviation of 0.305 minute. The winning​ c
uranmaximum [27]

Complete Question

The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.305 minute. The winning car, driven by Roger, finished in 185.85 minutes. The previous year's race had a mean finishing time of 110.7 with a standard deviation of 0.115 minute. The winning car that year, driven by Karen, finished in 110.48 minutes.

Find their respective z-scores.

 Who had the more convincing victory?

A. Roger​ had a more convincing victory because of a higher z-score.

B. Karen a more convincing victory because of a higher z-score.

C. Roger had a more convincing victory, because of a lower z-score.

D. Karen a more convincing victory because of a lower z-score.

Answer:

The correct option is  D

Step-by-step explanation:

From the question we are told that

  The mean of the current year  is  \mu_c =  186.32 \  minutes

   The standard deviation is  \sigma_c  =  0.305 \  minutes

   The time taken by  the winning car for the current year  is  x =  185.85 \ minutes

  The mean of the previous  year  is  \mu_p =  110.7 \  minutes

   The standard deviation the previous  year  is  \sigma_p  = 0.115  \  minutes

 The time taken by  the winning car for the previous year  is  y =   110.48 \ minutes    

Generally the z-score for current year is mathematically evaluated as

     z_c  =  \frac{x- \mu_c}{\sigma_c }

=>     z_c  =  \frac{ 185.85- 186.32}{0.305 }

=> z_c  = -1.536

Generally the z-score for previous year is mathematically evaluated as

     z_p  =  \frac{y- \mu_p}{\sigma_p }

=>     z_p  =  \frac{ 110.48-110.7}{0.115  }

=> z_p  = -1.913

From the value obtained we see that  z_p  <  z_c , Hence  Karen had a more convincing victory because of the lower z -score.

5 0
2 years ago
The following equation is being multiplied by the LCD. Complete the multiplication to eliminate the denominators
frosja888 [35]

Answer:

(x+2)(x-2) -1(3x)=(x-3)(x-2)

Step-by-step explanation:

x+2/3x - 1/x-2 = x-3/3x

\frac{x+2}{3x}-\frac{1}{x-2}=\frac{x-3}{3x}

LCD is (3x)(x-2). so we multiply the whole equation by LCD

(3x)(x-2)(\frac{x+2}{3x}-\frac{1}{x-2}=\frac{x-3}{3x})

We multiply each term by LCD

(3x)(x-2)(\frac{x+2}{3x})-(3x)(x-2)(\frac{1}{x-2})=(3x)(x-2)(\frac{x-3}{3x})

(x+2)(x-2) -1(3x)=(x-3)(x-2)

4 0
3 years ago
Read 2 more answers
Drinks cost 85p each.
bagirrra123 [75]
11 drinks because 85x11 = £9.35
7 0
3 years ago
I need a Math EXPERT!!! Please help me in my math homework. WILL MARK AS BRAINLIST.
qwelly [4]

velocity is the slope (which can be calculated after finding the derivative)  →  given function f(x), velocity = f'(x).

acceleration is the slope of the velocity (which can be calculated after finding the derivative of the velocity)  →  given function f(x), acceleration is f''(x)

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1a) A → B

f(x) = \frac{25}{3}x + 10

f'(x) = \frac{25}{3}

1b) B → C

f(x) = \frac{-15}{3}x + 50

f'(x) = \frac{-15}{3} = -5

1c) C → D

f(x) = 20

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Hope this helps!

5 0
3 years ago
Suppose that J and K are points on the number line.
rodikova [14]

Answer:

-7, -27

Step-by-step explanation:

J is at -17. K is 10 units from J.

Start at point J, -17:

a) If you go 10 units to the right, you end up at -17 + 10 = -7

b) If you go 10 units to the left, you end up at -17 - 10 = -27

J can be at -7 or at -27

Answer: -7, -27

8 0
3 years ago
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