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const2013 [10]
3 years ago
9

For what value of w makes the equation true? 135= w + 98

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
7 0
Answer:
w = 37

Explanation:
1. To solve this problem, you need to subtract both sides by 98. This will isolate the variable.

135 = w + 98 → 138 - 98 = w + 98 - 98

37 = w

2. Switch the sides

37 = w → w = 37

3. Your final answer should be w = 37
Ainat [17]3 years ago
4 0
W = 135-98 =37

First you substitue the 98 to the left side then since it changes to negative in the rule of substition you can easily subtract and get the answer
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2 numbers that adds up to 40 and can be multiplied and equals 36
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QUESTION 2
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The margin of error for a 95% confidence interval is 0.93.

mean (μ) = 23.4, standard deviation (σ) = 7.6, sample (n) = 254, confidence = 95% = 0.95

α = 1 - C = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025

The z score of α/2 is equal to the z score of 0.475 (0.5 - 0.025) which is equal to 1.96.

The margin of error (E) is given by:

E=z_\frac{\alpha}{2} *\frac{\sigma}{\sqrt{n} } \\\\E=1.96*\frac{7.6}{\sqrt{254} } \\\\E=0.93

The margin of error for a 95% confidence interval is 0.93.

Find out more at: brainly.com/question/10501147

4 0
3 years ago
A factory made 69 packs of mint-flavored gum and 31 packs of fruit-flavored gum. What percentage of the packs contained mint gum
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Answer:

69%

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if there are 69 packs of mint gum and 31 packs of friut gum 69+31=100

so 69 out of 100 (packs of mint gum) would be 69% of 100

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A linear equation exists for the following sets of ordered pairs: {(-1, 1), (0, 3), (-1/3, 7/3)}. The rule for the linear equati
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Geometry . Cosines / sines. Find a and round to the nearest 10th
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This is the good part of Trigonometry, actually measuring triangles. It's much better than all the identities around sine and cosine and the rest, which actually have more to do with circles than triangles.

This part of trig has a short menu:

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Law of Sines: \dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}

Triangle angles: A+B+C=180^\circ

and two special cases of the Law of Cosines, the Pythagorean Theorem

C=90^\circ, \quad \quad c^2=a^2+b^2

and the Collinear Points Theorem:

C=180^\circ, \quad \quad c^2=a^2+b^2 - 2 a b \cos 180^\circ = a^2+b^2+2ab=(a+b)^2

c = a+b

Here we choose Triangle Angles followed by Law of Sines:

A = 180 - 105 -15 = 60 degrees

\dfrac{a}{\sin 60^\circ}= \dfrac{2}{\sin 105^\circ}

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When I was a student we'd be expected to get \sin 105^\circ exactly and get

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But that was before online homework.

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