Answer:
This question doesn't really make sense...
Step-by-step explanation:
Please try to correct it.
To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
Answer:
31/5
Step-by-step explanation:
[f(4) - f(-1)] / 4-(-1)
Hi there! I can help you! 8 + (-9) + (-2). When adding negative integers, you have to subtract. 8 - 9 is -1 and -1 - 2 is -3. You would have to start at 8 and go to the left 11 times to land on -3. The sum to the problem is -3.
Answer: - 49
Step-by-step explanation:
f(x) = -2x - 1
g(x) = - 1
fg(x) = f ( - 1) , we just put in the value of g(x) , the next thing is to substitute - 1 for the value of x in f(x) , that is
fg(x) = -2( - 1) - 1
fg(x) = -2 + 2 - 1
fg(x) = -2 + 1
Therefore : fg(-5) means we will substitute -5 for x in fg(x) , that is
fg(-5) = -2 ( + 1
fg(-5) = -2(25) + 1
fg(-5) = -50 + 1
fg(-5) = -49