Rolling a die what is the probability of rolling two 4s in a row

1 answer:

muminat3 years ago

6 0

Probability =

(number of ways to succeed) / (total possible outcomes) .

There are 6 total possible outcomes of rolling one honest die.
Only one of them is a ' 4 '.

-- So the probability of rolling a '4' on the first roll is 1/6 .

-- The probability of rolling a '4' on the second roll is 1/6 .

-- The probability of BOTH events is

(1/6) x (1/6) = 1/36 = (2 and 7/9) percent .

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Realice la óperacion y exprese el resultado en notación científica (0,00000826) (235×10 elevado a -7) sobre 0,0017×10 elevado a

earnstyle [38]

Answer:

1,42 * 10 ^ -5

Step-by-step explanation:

La notación científica también se conoce como forma estándar.

Tenemos que realizar la siguiente operación y dejar el resultado en forma estándar.

Entonces;

0,00000826 * 235 × 10 ^ -7 / 0,0017 × 10 ^ -2

También;

8.26 * 10 ^ -6 * 2.35 * 10 ^ -5 / 1.7 * 10 ^ -5

= 19,411 * 10 ^ -11 / 1,7 * 10 ^ -5

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6 0

2 years ago

Write an equation that goes through (8,1) and is perpendicular to 2y + 4x =12

Serggg [28]

Answer:

2y -x + 6 = 0

Step-by-step explanation:

Here a equation and a point is given to us and we are interested in finding a equation which is perpendicular to the given equation and passes through the given point .

The given equation is ,

$\sf \longrightarrow 2y + 4x = 12 \\$

$\sf \longrightarrow 4x + 2y = 12$

Firstly convert this into slope intercept form , to find out the slope of the line.

$\sf \longrightarrow 2y = -4x +12\\$

$\sf \longrightarrow y =\dfrac{-4x+12}{2}\\$

$\sf \longrightarrow y =\dfrac{-4x}{2}+\dfrac{12}{2}\\$

$\sf \longrightarrow \red{ y = -2x + 6 }$

Now on comparing it to slope intercept form which is y = mx + c , we have ,

m = -2

And as we know that the product of slopes of two perpendicular lines is -1 . So the slope of the perpendicular line will be negative reciprocal of the slope of the given line. Therefore ,

$\sf \longrightarrow m_{\perp}=\dfrac{-1}{-2}=\red{\dfrac{1}{2}}$