Answer:
7.5 liters of a 10% antifreeze solution AND
7.5 liters of a 40% antifreeze solution
Step-by-step explanation:
According to the question,we were asked to find out how many liters of 10% anti freeze solution and 40% anti freeze each to make a 15 liters 25% mixture
Let’s call
the amount of liters needed of our 10% solution “x”. So, how
many liters do we need of the 40% solution? Well, there are 15
liters in total, x liters have been spoken for, so what remains
of our allotted 10 liters then, is 15-x.
Now let's solve for "x"
10% of x + 40% of (15 - x) = 25% of 15 liters
0.1x + 0.4(15 - x) = 0.25(15)
0.1x + 6 - 0.4x = 3.75
Collect the like terms and we have
0.3x = 2.25
x = 2.25 × 3
X = 7.5(Liters for the 10% anti freeze solution)
The 40% solution= 15 - 7.5 = 7.5 liters
Since "X" was used to fill for the unknown amount of 10% anti freeze solution,we have 7.5 liters of the 10% solution and another 7.5 liters for the 40% solution to end up with 15 liters of the desired 25% solution.
, which equals 
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