Question

g A canyon is 1200 meters deep at its deepest point. A rock is dropped from the rim above this point. How long will it take the rock to hit the canyon floor

Answer 1

Answer:

t = 15.6 s

Step-by-step explanation:

According to the kinematic equation:

$y_{f} = y_{0} + v_{0}*t - \frac{1}{2}gt^{2}$   (1)

Where:

$y_{f}$: is the final position = 1200 m

y₀: is the initial position = 0 m

V₀: is the initial speed = 0 m/s

g: is the gravity = 9.81 m/s²

t: is the time =?

From equation (1) we have:

$-1200 m = 0 + 0*t - \frac{1}{2}*9.81 m/s^{2}*t^{2}$      

$t^{2} = \frac{2*(1200 m)}{9.81 m/s{2}}$

$t = 15.6 s$

Therefore, it will take 15.6 seconds to the rock to hit the canyon floor.

I hope it helps you!