Answer:
x=√−16n−28 or x=−√−16n−28
Step-by-step explanation:
Step 1: Add -16n to both sides.
x2+16n+28+−16n=0+−16n
x2+28=−16n
Step 2: Add -28 to both sides.
x2+28+−28=−16n+−28
x2=−16n−28
Step 3: Take square root.
x=√−16n−28 or x=−√−16n−28
Answer:
what is this
Step-by-step explanation:
Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
